• 线段树(SegmentTree)基础模板


    线段树模板题来源:https://www.lintcode.com/problem/segment-tree-build/description

    201. 线段树的构造

    /**
     * Definition of SegmentTreeNode:
     * class SegmentTreeNode {
     * public:
     *     int start, end;
     *     SegmentTreeNode *left, *right;
     *     SegmentTreeNode(int start, int end) {
     *         this->start = start, this->end = end;
     *         this->left = this->right = NULL;
     *     }
     * }
     */
    
    
    class Solution {
    public:
        /*
         * @param start: start value.
         * @param end: end value.
         * @return: The root of Segment Tree.
         */
        SegmentTreeNode * build(int start, int end) {
            // write your code here
            if(start > end) return nullptr;
            auto root = new SegmentTreeNode(start, end);
            if(start < end){
                auto mid = (start + end) / 2;
                root->left = build(start, mid);
                root->right = build(mid+1, end);
            }
            
            return root;
        }
    };
    

    202. 线段树的查询

    /**
     * Definition of SegmentTreeNode:
     * class SegmentTreeNode {
     * public:
     *     int start, end, max;
     *     SegmentTreeNode *left, *right;
     *     SegmentTreeNode(int start, int end, int max) {
     *         this->start = start;
     *         this->end = end;
     *         this->max = max;
     *         this->left = this->right = NULL;
     *     }
     * }
     */
    
    class Solution {
    public:
        /**
         * @param root: The root of segment tree.
         * @param start: start value.
         * @param end: end value.
         * @return: The maximum number in the interval [start, end]
         */
        int query(SegmentTreeNode * root, int start, int end) {
            // write your code here
            auto mid = root->start + (root->end - root->start) / 2;
            if(start <= root->start && root->end <= end) return root->max;
            else if(start > mid) return query(root->right, start, end);
            else if(end <= mid) return query(root->left, start, end);
            else return max(query(root->left, start, mid), query(root->right, mid+1, end));
        }
    };
    

    203. 线段树的修改

    /**
     * Definition of SegmentTreeNode:
     * class SegmentTreeNode {
     * public:
     *     int start, end, max;
     *     SegmentTreeNode *left, *right;
     *     SegmentTreeNode(int start, int end, int max) {
     *         this->start = start;
     *         this->end = end;
     *         this->max = max;
     *         this->left = this->right = NULL;
     *     }
     * }
     */
    
    class Solution {
    public:
        /**
         * @param root: The root of segment tree.
         * @param index: index.
         * @param value: value
         * @return: nothing
         */
        void modify(SegmentTreeNode * root, int index, int value) {
            // write your code here
            if(root == nullptr || index > root->end || index < root->start) return;
            if(root->start == root->end) {
                root->max = value;
                return ;
            }
            auto mid = root->start + (root->end - root->start) / 2;
    
            if(index > mid){
                modify(root->right, index, value);
            } else {
                modify(root->left, index, value);
            }
            root->max = max(root->right->max, root->left->max);
            
        }
    };
    

    247. 线段树查询 II

    /**
     * Definition of SegmentTreeNode:
     * class SegmentTreeNode {
     * public:
     *     int start, end, count;
     *     SegmentTreeNode *left, *right;
     *     SegmentTreeNode(int start, int end, int count) {
     *         this->start = start;
     *         this->end = end;
     *         this->count = count;
     *         this->left = this->right = NULL;
     *     }
     * }
     */
    
    
    class Solution {
    public:
        /*
         * @param root: The root of segment tree.
         * @param start: start value.
         * @param end: end value.
         * @return: The count number in the interval [start, end]
         */
        int query(SegmentTreeNode * root, int start, int end) {
            // write your code here
            if(root == NULL) return 0;
            if(start <= root->start && root->end <= end) return root->count;
            auto mid = root->start + (root->end - root->start) / 2;
            if(end <= mid) return query(root->left, start, end);
            else if(start > mid) return query(root->right, start, end);
            else return query(root->left, start, mid) + query(root->right, mid + 1, end); 
        }
    };
    

    248. 统计比给定整数小的数的个数

    class Solution {
    public:
        /**
         * @param A: An integer array
         * @param queries: The query list
         * @return: The number of element in the array that are smaller that the given integer
         */
        struct SegmentTreeNode {
            int start, end, count;
            SegmentTreeNode* left, *right;
            SegmentTreeNode(int start_, int end_) : 
            start(start_), end(end_), count(0), left(nullptr), right(nullptr){}  
        };
        
        SegmentTreeNode* build(int start, int end){
            if(start > end) return nullptr;
            auto root = new SegmentTreeNode(start, end);
            if(start != end){
                auto mid = (start + end) / 2;
                root->left = build(start, mid);
                root->right = build(mid+1, end);
            }
            
            return root;
        }
        
        void add(SegmentTreeNode* root, int index, int val){
            auto mid = (root->start + root->end) / 2;
            if(root->start == root->end) {
                root->count += val;
                return;
            }
            
            if(index > mid){
                add(root->right, index, val);
            } else {
                add(root->left, index, val);
            }
            
            root->count += val;
            
        }
        
        int query(SegmentTreeNode* root, int start, int end){
            if(start <= root->start && root->end <= end) return root->count;
            auto mid = (root->start + root->end) / 2;
            if(start > mid) return query(root->right, start, end);
            else if(end <= mid) return query(root->left, start, end);
            else return query(root->right, mid+1, end) + query(root->left, start, mid);
        }
        vector<int> countOfSmallerNumber(vector<int> &A, vector<int> &queries) {
            // write your code here
            auto root = build(0, 10000);
            for(int i = 0; i < A.size(); i++){
                add(root, A[i], 1);
            }
            
            vector<int> ret;
            for(int i = 0;  i < queries.size(); i++){
                ret.push_back(query(root, 0, queries[i]-1));
            }
            
            return ret;
        }
    };
    

    249. 统计前面比自己小的数的个数

    class Solution {
    public:
        /**
         * @param A: an integer array
         * @return: A list of integers includes the index of the first number and the index of the last number
         */
         struct SegmentTreeNode {
            int start, end, count;
            SegmentTreeNode* left, *right;
            SegmentTreeNode(int start_, int end_) : 
            start(start_), end(end_), count(0), left(nullptr), right(nullptr){}  
        };
        
        SegmentTreeNode* build(int start, int end){
            if(start > end) return nullptr;
            auto root = new SegmentTreeNode(start, end);
            if(start != end){
                auto mid = (start + end) / 2;
                root->left = build(start, mid);
                root->right = build(mid+1, end);
            }
            
            return root;
        }
        
        void add(SegmentTreeNode* root, int index, int val){
            auto mid = (root->start + root->end) / 2;
            if(root->start == root->end) {
                root->count += val;
                return;
            }
            
            if(index > mid){
                add(root->right, index, val);
            } else {
                add(root->left, index, val);
            }
            
            root->count += val;
            
        }
        
        int query(SegmentTreeNode* root, int start, int end){
            if(start > end) return 0;
            if(start <= root->start && root->end <= end) return root->count;
            auto mid = (root->start + root->end) / 2;
            if(start > mid) return query(root->right, start, end);
            else if(end <= mid) return query(root->left, start, end);
            else return query(root->right, mid+1, end) + query(root->left, start, mid);
        }
        vector<int> countOfSmallerNumberII(vector<int> &A) {
            // write your code here
            auto root = build(0, 10000);
            vector<int> ret;
            for(int i = 0; i < A.size(); i++){
                auto c = query(root, 0, A[i]-1);
               
                ret.push_back(c);
              
                add(root, A[i], 1);
            }
    
            return ret;
        }
    };
    
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  • 原文地址:https://www.cnblogs.com/qbits/p/11273469.html
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