# -*- coding:utf-8 -*- import threading,time #通过获取锁对象,访问共有数据,最后释放锁来完成一次操作, # 一旦某个线程获取了锁,当这个线程被切换时,下个个进程无法获取该公有数据 def func(): #开始处理数据 global n lock.acquire() #获取 a=n+1 time.sleep(0.00001) n =a lock.release() #释放 # 结束处理 print(n) if __name__ == '__main__': n=0 lock=threading.Lock() li =[] start_time = time.time() for i in range(500): t=threading.Thread(target=func,args=()) li.append(t) t.start() for i in li: i.join() #等待子线程全部执行完 end_time = time.time()-start_time print(n,end_time) #1000
# -*- coding:utf-8 -*- import threading import time, random def eating(): print("我饿了-0-") event.wait() print('去吃饭的路上...') def makeing(): print('做饭中...') time.sleep(random.randint(1,2)) print('做好了,快来!') event.set() if __name__ == '__main__': event=threading.Event() t1 = threading.Thread(target=eating) t2 = threading.Thread(target=makeing) t1.start() t2.start() # 做饭中 # 做好了,快来... # 去吃饭的路上...
11
# -*- coding:utf-8 -*- import threading,time def func(): #开始处理数据 global n #可以改变函数外的变量 a=n+1 time.sleep(0.0001) n =a # 结束处理 if __name__ == '__main__': n=0 li =[] for i in range(1000): t=threading.Thread(target=func,args=()) li.append(t) t.start() print(n) #可能有多个线程同时拿到同一个值,所以会出现大量重复值,这就需要为数据进行加锁 for i in li: i.join() #等待子线程全部执行完,1000个子线程 print("n:",n) #155