• hdu 5655 CA Loves Stick


    CA Loves Stick

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)
    Total Submission(s): 612    Accepted Submission(s): 214


    Problem Description
    CA loves to play with sticks.
    One day he receives four pieces of sticks, he wants to know these sticks can spell a quadrilateral.
    (What is quadrilateral? Click here: https://en.wikipedia.org/wiki/Quadrilateral)
     
    Input
    First line contains T denoting the number of testcases.
    T testcases follow. Each testcase contains four integers a,b,c,d in a line, denoting the length of sticks.
    1T1000, 0a,b,c,d2631
     
    Output
    For each testcase, if these sticks can spell a quadrilateral, output "Yes"; otherwise, output "No" (without the quotation marks).
     
    Sample Input
    2
    1 1 1 1
    1 1 9 2
     
    Sample Output
    Yes
    No
     
    Source
     
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    wange2014   |   We have carefully selected several similar problems for you:  5659 5658 5657 5654 5653 
     
    打BC的时候遇到的第一题,本来很简单的一道题,数据范围有点坑,错了三次,坑死宝宝了。
    四边形定则:三边之后一定要大于第四边。
     
    题意:给你四条边的长度,判断是否是个四边形,是则Yes,不是则No。注意数据的范围!!!
     
    附上代码:
     
     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 #include <algorithm>
     5 using namespace std;
     6 int main()
     7 {
     8     __int64 a[5],m;
     9     int T,i,j;
    10     scanf("%d",&T);
    11     while(T--)
    12     {
    13         for(i=0; i<4; i++)
    14             scanf("%I64d",&a[i]);
    15         sort(a,a+4);
    16         if(a[0]==0)
    17         {
    18             printf("No
    ");
    19             continue;
    20         }
    21         m=a[3]-a[1]-a[2];
    22         if(m>=a[0])
    23             printf("No
    ");
    24         else
    25             printf("Yes
    ");
    26     }
    27     return 0;
    28 }
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  • 原文地址:https://www.cnblogs.com/pshw/p/5351406.html
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