• loj2042 「CQOI2016」不同的最小割


    分治+最小割
    看到题解的第一句话是这个就秒懂了,然后乱七八糟的错误、越界、RE……

    #include <algorithm>
    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <queue>
    #include <set>
    using namespace std;
    int n, m, uu, vv, ww, hea[855], cnt, a[855], ss, tt, lev[855], tmp[855], cur[855];
    int maxFlow;
    const int oo=0x3f3f3f3f;
    queue<int> d;
    set<int> se;
    struct Edge{
    	int too, nxt, val;
    }edge[17005];
    void add_edge(int fro, int too, int val){
    	edge[cnt].nxt = hea[fro];
    	edge[cnt].too = too;
    	edge[cnt].val = val;
    	hea[fro] = cnt++;
    }
    bool bfs(){
    	memset(lev, 0, sizeof(lev));
    	lev[ss] = 1;
    	d.push(ss);
    	while(!d.empty()){
    		int x=d.front();
    		d.pop();
    		for(int i=hea[x]; i!=-1; i=edge[i].nxt){
    			int t=edge[i].too;
    			if(!lev[t] && edge[i].val>0){
    				lev[t] = lev[x] + 1;
    				d.push(t);
    			}
    		}
    	}
    	return lev[tt]!=0;
    }
    int dfs(int x, int lim){
    	if(x==tt)	return lim;
    	int addFlow=0;
    	for(int &i=cur[x]; i!=-1; i=edge[i].nxt){
    		int t=edge[i].too;
    		if(lev[t]==lev[x]+1 && edge[i].val>0){
    			int tmp=dfs(t, min(lim-addFlow, edge[i].val));
    			edge[i].val -= tmp;
    			edge[i^1].val += tmp;
    			addFlow += tmp;
    			if(addFlow>=lim)	break;
    		}
    	}
    	return addFlow;
    }
    void dinic(){
    	maxFlow = 0;
    	while(bfs()){
    		for(int i=1; i<=n; i++)
    			cur[i] = hea[i];
    		maxFlow += dfs(ss, oo);
    	}
    }
    void solve(int l, int r){
    	if(l>=r)	return ;
    	for(int i=0; i<cnt; i+=2)
    		edge[i].val = edge[i^1].val = (edge[i].val + edge[i^1].val) >> 1;
    	ss = a[l]; tt = a[r];
    	dinic();
    	se.insert(maxFlow);
    	int pu=l, pv=r;
    	for(int i=l; i<=r; i++)
    		if(lev[a[i]])
    			tmp[pu++] = a[i];
    		else
    			tmp[pv--] = a[i];
    	for(int i=l; i<=r; i++)
    		a[i] = tmp[i];
    	solve(l, pu-1);
    	solve(pv+1, r);
    }
    int main(){
    	memset(hea, -1, sizeof(hea));
    	cin>>n>>m;
    	for(int i=1; i<=m; i++){
    		scanf("%d %d %d", &uu, &vv, &ww);
    		add_edge(uu, vv, ww);
    		add_edge(vv, uu, ww);
    	}
    	for(int i=1; i<=n; i++)
    		a[i] = i;
    	solve(1, n);
    	cout<<se.size()<<endl;
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/poorpool/p/8945452.html
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