• Map基础知识01-ConcurrentHashMap


         ConcurrentHashMap相较于HashMap最大的特点就是线程安全的。

         这篇随笔主要了解以下ConcurrentHashMap的基本知识.

    环境:JDK1.8

    1.初始化

    构造函数

    • 1.可以看出默认的初始容量是16;

    • 2.默认的平衡因子是0.75f

    
    //默认初始容量时16
    private static final int DEFAULT_CAPACITY = 16;
    
    //平衡因子默认是0.75
    private static final float LOAD_FACTOR = 0.75f;
    //最大容量  1073741824
    private static final int MAXIMUM_CAPACITY = 1 << 30;
    //设置控制容量sizeCtl
    public ConcurrentHashMap(int initialCapacity,
                             float loadFactor, int concurrencyLevel) {
        if (!(loadFactor > 0.0f) || initialCapacity < 0 || concurrencyLevel <= 0)
            throw new IllegalArgumentException();
        if (initialCapacity < concurrencyLevel)   // Use at least as many bins
            initialCapacity = concurrencyLevel;   // as estimated threads
        long size = (long)(1.0 + (long)initialCapacity / loadFactor);
        int cap = (size >= (long)MAXIMUM_CAPACITY) ?
            MAXIMUM_CAPACITY : tableSizeFor((int)size);
        this.sizeCtl = cap;
    } 
    

    值的增删改查操作

    值的存储过程

    先看一下代码:

    static final int TREEIFY_THRESHOLD = 8;
    
    final V putVal(K key, V value, boolean onlyIfAbsent) {
        if (key == null || value == null) throw new NullPointerException();
        int hash = spread(key.hashCode()); //获取hash值
        int binCount = 0;
        for (Node<K,V>[] tab = table;;) {//如果初始化,则通过循环保证数据插入
            Node<K,V> f; int n, i, fh;
            if (tab == null || (n = tab.length) == 0)//如果存储数据的Node数组为空,初始化数组
                tab = initTable();
            else if ((f = tabAt(tab, i = (n - 1) & hash)) == null) {//当hash定位为空时,则通过CAS插入数据
                if (casTabAt(tab, i, null,
                             new Node<K,V>(hash, key, value, null)))
                    break;                   // no lock when adding to empty bin
            }
            else if ((fh = f.hash) == MOVED)//Node数组进行扩容,原数组的数据进行转移
                tab = helpTransfer(tab, f);
            else {
                V oldVal = null;
                synchronized (f) {
                    if (tabAt(tab, i) == f) { 
                        if (fh >= 0) {//如果hash相同,并且不是红黑树节点时
                            binCount = 1;
                            for (Node<K,V> e = f;; ++binCount) {//如果是链表的节点会一直循环
                                K ek;
                                if (e.hash == hash &&
                                    ((ek = e.key) == key ||
                                     (ek != null && key.equals(ek)))) {//如果节点的key相同,直接替换
                                    oldVal = e.val;
                                    if (!onlyIfAbsent)
                                        e.val = value;
                                    break;
                                }
                                Node<K,V> pred = e;
                                if ((e = e.next) == null) {//如果key不相同,则形成单向链表
                                    pred.next = new Node<K,V>(hash, key,
                                                              value, null);
                                    break;
                                }
                            }
                        }
                        else if (f instanceof TreeBin) {//判断节点是否是红黑树
                            Node<K,V> p;
                            binCount = 2;
                            if ((p = ((TreeBin<K,V>)f).putTreeVal(hash, key,
                                                           value)) != null) {//如果是红黑树,保存进数据返回红黑树的替换节点,如果是新插入节点则返回null
                                oldVal = p.val;
                                if (!onlyIfAbsent)
                                    p.val = value;
                            }
                        }
                    }
                }
                if (binCount != 0) {
                    if (binCount >= TREEIFY_THRESHOLD)//如果链表长度超过8,则把链表变成红黑树
                        treeifyBin(tab, i);
                    if (oldVal != null)
                        return oldVal;
                    break;
                }
            }
        }
        addCount(1L, binCount);
        return null;
    }
    

    执行逻辑:如下图所示

    红黑树的插入,查找,删除操作:

    可以查看我的另一篇博客,这个是根据ConcurrentHashMap中红黑树的代码进行分析的。

    博客地址:https://www.cnblogs.com/perferect/p/13569671.html

    ConcurrentHashMap的数据存储结构:

         经过上面的代码,我们可以分析出来,ConcurrentHashMap的数据结构是,数组+链表+红黑树的结构。

    • 当链表节点个数超过8个时,才能判断是否要生成红黑树

    • 当Node数组长度超过64,链表才能生成红黑树,否则重新resizeNode数组

    值的查找

    public V get(Object key) {
            Node<K,V>[] tab; Node<K,V> e, p; int n, eh; K ek;
            int h = spread(key.hashCode());
            if ((tab = table) != null && (n = tab.length) > 0 &&
                (e = tabAt(tab, (n - 1) & h)) != null) {
                if ((eh = e.hash) == h) {//如果在数组中key相等,返回查找值
                    if ((ek = e.key) == key || (ek != null && key.equals(ek)))
                        return e.val;
                }
                else if (eh < 0)//查找红黑树中的节点
                    return (p = e.find(h, key)) != null ? p.val : null;
                while ((e = e.next) != null) {//查找链表中对应的值
                    if (e.hash == h &&
                        ((ek = e.key) == key || (ek != null && key.equals(ek))))
                        return e.val;
                }
            }
            return null;
        }
    
    

    值的删除操作

    先看一下代码:

    • 逻辑和插入节点有点类似,看一下代码就能理解
    public V remove(Object key) {
            return replaceNode(key, null, null);
        }
     final V replaceNode(Object key, V value, Object cv) {
            int hash = spread(key.hashCode());//获取hash
            for (Node<K,V>[] tab = table;;) {
                Node<K,V> f; int n, i, fh;
                if (tab == null || (n = tab.length) == 0 ||
                    (f = tabAt(tab, i = (n - 1) & hash)) == null)//如果Node数组长度为0,或者hash节点为空,直接结束
                    break;
                else if ((fh = f.hash) == MOVED)//如果Node数组在扩容中先进行扩容
                    tab = helpTransfer(tab, f);
                else {
                    V oldVal = null;
                    boolean validated = false;
                    synchronized (f) {
                        if (tabAt(tab, i) == f) {//hash节点没变
                            if (fh >= 0) {//是数组或链表结构时
                                validated = true;
                                for (Node<K,V> e = f, pred = null;;) {
                                    K ek;
                                    if (e.hash == hash &&
                                        ((ek = e.key) == key ||
                                         (ek != null && key.equals(ek)))) {// key值相同时
                                        V ev = e.val;
                                        if (cv == null || cv == ev ||
                                            (ev != null && cv.equals(ev))) {
                                            oldVal = ev;
                                            if (value != null)
                                                e.val = value;
                                            else if (pred != null)//逐个遍历e开头的链表
                                                pred.next = e.next;
                                            else
                                                setTabAt(tab, i, e.next);//替换链表e,为e的next,如果为数组的话,next为null
                                        }
                                        break;
                                    }
                                    pred = e;
                                    if ((e = e.next) == null)//如果是链表结构,移动节点
                                        break;
                                }
                            }
                            else if (f instanceof TreeBin) {//如果是红黑树
                                validated = true;
                                TreeBin<K,V> t = (TreeBin<K,V>)f;
                                TreeNode<K,V> r, p;
                                if ((r = t.root) != null &&
                                    (p = r.findTreeNode(hash, key, null)) != null) {//判断红黑树是否存在并且有这个节点
                                    V pv = p.val;
                                    if (cv == null || cv == pv ||
                                        (pv != null && cv.equals(pv))) {
                                        oldVal = pv;
                                        if (value != null)
                                            p.val = value;
                                        else if (t.removeTreeNode(p))//移除红黑树中的节点
                                            setTabAt(tab, i, untreeify(t.first));
                                    }
                                }
                            }
                        }
                    }
                    if (validated) {
                        if (oldVal != null) {
                            if (value == null)
                                addCount(-1L, -1);
                            return oldVal;
                        }
                        break;
                    }
                }
            }
            return null;
        }
    
    
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  • 原文地址:https://www.cnblogs.com/perferect/p/13213931.html
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