You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
简单链表题
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) { int flag = 0; if(l1 == NULL && l2 == NULL)return NULL; ListNode * head = new ListNode(0); ListNode * tmp =head; while(l1!=NULL && l2!=NULL) { int temp = l1->val + l2->val + flag; flag = temp/10; ListNode *node = new ListNode(temp%10); tmp->next = node; tmp = tmp -> next; l1 = l1->next; l2 = l2->next; } while(l1!=NULL) { int temp = l1->val + flag; flag = temp/10; ListNode *node = new ListNode(temp%10); tmp->next = node; tmp = tmp -> next; l1 = l1->next; } while(l2!=NULL) { int temp = l2->val + flag; flag = temp/10; ListNode *node = new ListNode(temp%10); tmp->next = node; tmp = tmp -> next; l2 = l2->next; } if(flag == 1) { ListNode *node = new ListNode(1); tmp->next = node; } head =head->next; return head; } };