简单的Oracle列转行函数Listagg示例:
CREATE TABLE tbl_test (catalog VARCHAR(1),product VARCHAR(2),amount NUMBER); INSERT INTO tbl_test VALUES('A','A1',1); INSERT INTO tbl_test VALUES('A','A1',2); INSERT INTO tbl_test VALUES('B','B1',3); INSERT INTO tbl_test VALUES('B','B2',4); INSERT INTO tbl_test VALUES('B','B2',5); INSERT INTO tbl_test VALUES('C','C1',6); INSERT INTO tbl_test VALUES('C','C1',7); INSERT INTO tbl_test VALUES('C','C2',8); INSERT INTO tbl_test VALUES('C','C2',9); COMMIT;
SELECT * FROM tbl_test; CATALOG PRODUCT AMOUNT ------- ------- ---------- A A1 1 A A1 2 B B1 3 B B2 4 B B2 5 C C1 6 C C1 7 C C2 8 C C2 9 9 rows selected
SELECT LISTAGG(product,',') WITHIN GROUP( ORDER BY amount) AS lst FROM tbl_test; LST ---------------------------- A1,A1,B1,B2,B2,C1,C1,C2,C2
SELECT catalog, LISTAGG(product,',') WITHIN GROUP( ORDER BY amount) as lst FROM tbl_test GROUP BY catalog; CATALOG LST ------- ----------------- A A1,A1 B B1,B2,B2 C C1,C1,C2,C2
SELECT LISTAGG(product||'-'||amount,',') WITHIN GROUP( ORDER BY amount) over (partition by catalog) AS lst FROM tbl_test ; LST ---------------------- A1-1,A1-2 A1-1,A1-2 B1-3,B2-4,B2-5 B1-3,B2-4,B2-5 B1-3,B2-4,B2-5 C1-6,C1-7,C2-8,C2-9 C1-6,C1-7,C2-8,C2-9 C1-6,C1-7,C2-8,C2-9 C1-6,C1-7,C2-8,C2-9 9 rows selected
SELECT * FROM tbl_test pivot ( sum(amount) FOR(catalog) IN('A','B','C') ) ORDER BY 1; PRODUCT 'A' 'B' 'C' ------- ---------- ---------- ---------- A1 3 B1 3 B2 9 C1 13 C2 17
SELECT product,EXTRACT(catalog_xml,'//column[@name="SUM(AMOUNT)"]/text()') AS sum FROM tbl_test pivot xml( sum(amount) FOR(catalog) IN(ANY) ) ORDER BY 1; PRODUCT SUM ------- ------- A1 3 B1 3 B2 9 C1 13 C2 17