利用shell找出15分钟内修改的文件

如果你的文件只是生成不会修改的话，可以这样：

find * -mmin -15 2>/dev/null 

如果可能修改，则需要这样（先创建一个 15 分之前的时间戳的文件，然后找比这个文件新的文件）： 
touch -t $(date -d "15 min ago" +%Y%m%d%H%M) temp.tmp
find * -newer temp.tmp 2>/dev/null
rm -rf temp.tmp

脚本如下：

#!/bin/bash

echo -en "e[1;32mPlease enter the required time: e[0m"
read input

rm -rf /tmp/error/*

cd /u01/app/siebel/ses/siebsrvr/enterprises/FFP_82/FFPAPP01/log

touch -t $(date -d "$input min ago" +%Y%m%d%H%M) /tmp/error/temp.tmp
filename=`find * -newer /tmp/error/temp.tmp 2>/dev/null`

for i in $filename:
do
logname=`echo $i|awk -F'_' '{print $1}'`
echo "++++++++++++++++++++++++++++++++++++++++++++++++++++++++++" >> /tmp/error/$logname-`date +%F`.log
echo $i >> /tmp/error/$logname-`date +%F`.log
echo "++++++++++++++++++++++++++++++++++++++++++++++++++++++++++" >> /tmp/error/$logname-`date +%F`.log
sed -n '/error/p; /Error/p; /fail/p; /Fail/p' $i >> /tmp/error/$logname-`date +%F`.log
if [ $? -eq 0 ];then
echo "create log successfully! $i /tmp/error/$logname-`date +%F`.log"
else
echo "create log fail. please check it out"
fi
done

if [ $? -eq 0 ];then
echo -e 'e[1;32mcreate log successfully! congratulation!e[0m'
else
echo -e 'e[1;31mcreate log fail. please check it out!e[0m'
fi