PAT1002

1002. A+B for Polynomials (25)

时间限制

400 ms

内存限制

32000 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

This time, you are supposed to find A+B where A and B are two polynomials.

Input

Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 a_N1 N2 a_N2 ... NK a_NK, where K is the number of nonzero terms in the polynomial, Ni and a_Ni (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10，0 <= NK < ... < N2 < N1 <=1000.

Output

For each test case you should output the sum of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate to 1 decimal place.

Sample Input

2 1 2.4 0 3.2
2 2 1.5 1 0.5

Sample Output

3 2 1.5 1 2.9 0 3.2

AC源码：

#include 

double polyBuf[1001];

void initial()
{
    for(int i=0; i<1001; i++)
    {
        polyBuf[i] = 0.0;
    }
}

int main()
{
    initial();

    int k;
    while(scanf("%d", &k) != EOF)
    {
        int n;
        double a;
        for(int i=0; i=0; i--)
        {
            if(polyBuf[i] != 0)
            {
                cnt++;
            }
        }

        printf("%d", cnt);

        for(int i=1000; i>=0; i--)
        {
            if(polyBuf[i] != 0)
            {
                printf(" %d %.1lf", i, polyBuf[i]);
            }
        }

        printf("\n");
    }

    return 0;
}

提交结果：

点评：

一次A过，None