1. Question
717. 1-bit and 2-bit Characters
https://leetcode.com/problems/1-bit-and-2-bit-characters/
We have two special characters. The first character can be represented by one bit 0
. The second character can be represented by two bits (10
or 11
).
Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.
Example 1:
Input: bits = [1, 0, 0] Output: True Explanation: The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.
Example 2:
Input: bits = [1, 1, 1, 0] Output: False Explanation: The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.
Note:
1 <= len(bits) <= 1000
.bits[i]
is always0
or1
2. Solution:
class Solution:
def dfs(self, bits):
size = len(bits)
if size == 1:
return True
if size == 2:
if bits[0] == 1:
return False
else:
return True
if size >= 3:
if bits[0] == 1:
return self.dfs(bits[2:])
else:
return self.dfs(bits[1:])
def isOneBitCharacter(self, bits):
"""
:type bits: List[int]
:rtype: bool
"""
return self.dfs(bits)