求按小时统计的语句 表:issue 字段: id:1 time:2012-04-01 08:15:00 count:12 。。。。。 按小时统计count总数,结果如下 1 2012-04-01 8:00~9:00 134 2 2012-04-01 9:00~10:00 134 ------解决方案-------------------- 如果结果前面的数字是你要的计数的话,那自己另加一个计数列就是了: SQL code mysql> select * from issue; +----+---------------------+-------+ | id | time | count | +----+---------------------+-------+ | 1 | 2012-04-01 08:15:00 | 12 | | 2 | 2012-04-01 09:15:00 | 12 | | 3 | 2012-04-01 08:25:00 | 12 | | 4 | 2012-04-01 10:15:00 | 12 | | 5 | 2012-04-01 09:15:00 | 12 | +----+---------------------+-------+ 5 rows in set (0.00 sec) mysql> select concat(date_format(time, "%Y-%m-%d %k:00~"), hour(time)+1, ":00") as 'time', sum(`count`) as 'count' -> from issue -> group by left(time, 13); +------------------------+-------+ | time | count | +------------------------+-------+ | 2012-04-01 8:00~9:00 | 24 | | 2012-04-01 9:00~10:00 | 24 | | 2012-04-01 10:00~11:00 | 12 | +------------------------+-------+ 3 rows in set (0.00 sec) ------解决方案-------------------- 恩 group by left(time, 13); ------解决方案-------------------- select DATE_FORMAT(time,'%Y-%m-%d %H:00'),sum(count) from issue group by DATE_FORMAT(time,'%Y-%m-%d %H:00') ------解决方案-------------------- select Date_format(time,'%Y-%M-%d %H:00'),SUM(COUNT) FROM issue group byy DATA_FORMAR(time,'%Y-%m-%d %h:00)