Question
Solution
题目大意:判断两个字符串是否具有相同的结构
思路:构造一个map,存储每个字符的差,遍历字符串,判断两个两个字符串中相同位置字符的差是否相同
Java实现:
public boolean isIsomorphic(String s, String t) {
Map<String, Integer> map = new HashMap<>();
for (int i=0; i<s.length(); i++) {
char c1 = s.charAt(i);
char c2 = t.charAt(i);
String key1 = "s_" + c1;
String key2 = "t_" + c2;
if (map.get(key1) == null) {
map.put(key1, c1 - c2);
} else if (map.get(key1) != c1 - c2) {
return false;
}
if (map.get(key2) == null) {
map.put(key2, c2 - c1);
} else if (map.get(key2) != c2 - c1) {
return false;
}
}
return true;
}
别人的实现:
public boolean isIsomorphic(String s1, String s2) {
int[] m = new int[512];
for (int i = 0; i < s1.length(); i++) {
if (m[s1.charAt(i)] != m[s2.charAt(i)+256]) return false;
m[s1.charAt(i)] = m[s2.charAt(i)+256] = i+1;
}
return true;
}