• 通用动态树(Link-Cut Tree)模板


    一个没有维护任何东西的动态树模板

    忘了怎么写可以直接来粘

    int ch[300010][2], fa[300010], st[300010];
    bool lazy[300010];
    
    bool nroot(int x) { return ch[fa[x]][0] == x || ch[fa[x]][1] == x; }
    void rev(int x) { swap(ch[x][0], ch[x][1]), lazy[x] ^= 1; }
    void pushup(int x) { /*维护一个pre*/ }
    
    void pushdown(int x)
    {
    	if (lazy[x])
    	{
    		if (ch[x][0]) rev(ch[x][0]);
    		if (ch[x][1]) rev(ch[x][1]);
    		lazy[x] = 0;
    	}
    }
    
    void rotate(int x)
    {
    	int y = fa[x], z = fa[y], k = ch[y][1] == x, w = ch[x][k ^ 1];
    	if (nroot(y)) { ch[z][ch[z][1] == y] = x; } ch[x][k ^ 1] = y, ch[y][k] = w;
    	if (w) { fa[w] = y; } fa[y] = x; fa[x] = z; pushup(y), pushup(x);
    }
    
    void splay(int x)
    {
    	int y = x, top = 0;
    	st[++top] = y;
    	while (nroot(y)) st[++top] = y = fa[y];
    	while (top > 0) pushdown(st[top--]);
    	while (nroot(x))
    	{
    		int y = fa[x], z = fa[y];
    		if (nroot(y)) rotate((ch[y][1] == x) ^ (ch[z][1] == y) ? x : y);
    		rotate(x);
    	}
    	pushup(x);
    }
    
    void access(int x)
    {
    	for (int y = 0; x > 0; x = fa[y = x])
    		splay(x), ch[x][1] = y, pushup(x);
    }
    
    void makert(int x)
    {
    	access(x), splay(x), rev(x);
    }
    
    int findrt(int x)
    {
    	access(x), splay(x);
    	while (ch[x][0]) pushdown(x), x = ch[x][0];
    	return x;
    }
    
    void link(int x, int y)
    {
    	makert(x);
    	if (findrt(y) != x) fa[x] = y;
    }
    
    void cut(int x, int y)
    {
    	makert(x);
    	if (findrt(y) == x && fa[x] == y && ch[x][1] == 0)
    		ch[y][0] = fa[x] = 0, pushup(y);
    }
    

    upd:压行Link-Cut Tree模板

    bool nroot(int x) { return ch[fa[x]][0] == x || ch[fa[x]][1] == x; }
    void rev(int x) { swap(ch[x][0], ch[x][1]), lazy[x] ^= 1; }
    void pushup(int x) { /*维护一个pre*/ }
    void pushdown(int x) { if (lazy[x]) { if (ch[x][0]) { rev(ch[x][0]); } if (ch[x][1]) { rev(ch[x][1]); } lazy[x] = 0; } }
    void rotate(int x)
    {
    	int y = fa[x], z = fa[y], k = ch[y][1] == x, w = ch[x][k ^ 1];
    	if (nroot(y)) { ch[z][ch[z][1] == y] = x; } ch[x][k ^ 1] = y, ch[y][k] = w;
    	if (w) { fa[w] = y; } fa[y] = x; fa[x] = z; pushup(y), pushup(x);
    }
    void splay(int x)
    {
    	int y = x, top = 0; st[++top] = y; while (nroot(y)) { st[++top] = y = fa[y]; } while (top > 0) { pushdown(st[top--]); }
    	while (nroot(x)) { int y = fa[x], z = fa[y]; if (nroot(y)) { rotate((ch[y][1] == x) ^ (ch[z][1] == y) ? x : y); } rotate(x); }
    }
    void access(int x) { for (int y = 0; x > 0; x = fa[y = x]) splay(x), ch[x][1] = y, pushup(x); }
    void makert(int x) { access(x), splay(x), rev(x); }
    int findrt(int x) { access(x), splay(x); while (ch[x][0]) { pushdown(x), x = ch[x][0]; } return x; }
    void link(int x, int y) { makert(x); if (findrt(y) != x) fa[x] = y; }
    void cut(int x, int y) { makert(x); if (findrt(y) == x && fa[x] == y && ch[x][1] == 0) ch[y][0] = fa[x] = 0, pushup(y); }
    
  • 相关阅读:
    Android第二次作业
    六月十二课下作业
    第十三周课下作业
    第十三周上机练习
    第十二周课下作业
    第十二周上机作业
    十一周课下作业
    第十一周上机作业
    第十周上机练习
    android-7增删改查
  • 原文地址:https://www.cnblogs.com/oier/p/10425484.html
Copyright © 2020-2023  润新知