Write a program named "ReverseDigits ", it generates the number that has the same digits in the reverse order, as illustrated by this sample run:
---------------------------------ReverseDigits 类---------------------------------
package chapter4;
import java.util.InputMismatchException;
import java.util.Scanner;
/*
* 倒序输出int类型的数字,比如1792，输出为2971
*
* */
public class ReverseDigits {
int N=0;
int subnum=0;
public void run(){
System.out.println("please input number : ");
Scanner input=new Scanner(System.in);
try {
int num=input.nextInt();
while (num>0){
subnum=num%10;
num=num/10;
N =(N+subnum)*10; //算法的关键~
}
N =N/10; //算法的关键
System.out.println("the ReverseDigits is :"+ N);
} catch(InputMismatchException e1){
System.out.println("输入数据类型不符,应为int 类型");
}
}
}
--------------------------主函数调用--------------------------------
package chapter4;
public class main4 {
/**
* 主要运行<<the art and science of java>>第4章的练习题目
*/
public static void main(String[] args) {
ReverseDigits rev1=new ReverseDigits();
rev1.run();
}
}