c++ 实验一

#include<iostream>
using namespace std;
int main() {
    int day;
    cin >> day;
    switch (day) {
    case 1:
    case 2:
    case 3:
    case 4:
    case 5:cout << "workday. Let’s work hard" << endl;
        break;
    case 6:
    case 7:cout << "weekend. Let’s have a rest." << endl;
        break;
    default:cout << "Day out of range Sunday...Saturday" << endl;
        break;
    }
    return 0;
}

#include<iostream>
using namespace std;
int main() {
    int n, i, j = 0, digit = 0, right_digit = 0, t;
    cout << "Enter the number:";
    cin >> n;
    cout << "The number in reverse order is";
    t = n;
    do {
        n /= 10;
        digit += 1;
    } while (n != 0);
           n = t;//复位
    for (i =digit;i>0;i--){
        j=n % 10;
        n /= 10;
        right_digit += j * pow(10, i - 1);
    }
    cout << right_digit<< endl;
    return 0;
}

代码写完后再看就觉得简单多了，但是实际刚才做的时候遇到了许多困难，然后一一解决才最终完成

应该是我还不太熟练吧，接下来需要多加练习

第二题复位这一步开始没写，导致结果是0，这需要注意

计算正确数字时位数是乘10的（n-1）次，也需要注意