• ajax练习


    html代码

        <div>
            <label for="userid">ID</label>
            <input type="text" id="userid">
            <button id="submit">查询</button>
        </div>
    
        <div id="show">
    
        </div>
        <script>
            var id=document.getElementById('userid');
            var submit=document.getElementById('submit');
            submit.addEventListener('click',cx);
            function cx(e){
                var input=id.value;
                var xhr=new XMLHttpRequest();
                xhr.open('GET','user.php?user_id='+input,'true')
                xhr.send();
                xhr.onload=function(){
                    document.getElementById('show').innerHTML=xhr.responseText;
                }
            }
        </script>

    php代码

    <?php
    $userId = isset($_GET['user_id']) ? $_GET['user_id'] : null;
    
    $userInfo = [
        ['user_id'=>1, 'username'=>'苍老师', 'gender'=>'', 'age'=>26],
        ['user_id'=>2, 'username'=>'波老师', 'gender'=>'', 'age'=>23],
        ['user_id'=>3, 'username'=>'黑老师', 'gender'=>'', 'age'=>33],
    ];
    
    $res = '';
    foreach ($userInfo as $user) {
        if ($user['user_id'] === intval($userId)) {
            $res .= $user['user_id'].'---'.$user['username'].'---'.$user['gender'].'---'.$user['age'];
        }
    }
    
    echo empty($res) ? '<span style="color: red;">没有找到该用户名</span>' : $res;
    exit;
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  • 原文地址:https://www.cnblogs.com/no000000/p/13588665.html
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