• poj1664刷水报告


    View Code
     1 #include<stdio.h>
     2 
     3 int main()
     4 {
     5     int m, n, k[11][11], t;
     6     k[0][0] = 1;
     7     for (m = 0; m < 11; m++)
     8     {
     9         k[m][1] = 1;
    10         for (n = 2; n <= m; n++)
    11             k[m][n] = k[m][n - 1] + k[m - n][n];
    12         while (n < 11)
    13             k[m][n++] = k[m][m];
    14     }
    15     scanf("%d", &t);
    16     while (t--)
    17     {
    18         scanf("%d %d", &m, &n);
    19         printf("%d\n", k[m][n]);
    20     }
    21     return 0;
    22 }

    当n>m时,f(m,n)=f(m,m)(其它的是空盘子),当n=1时f(m,n)=1(只有一个盘子),否则f(m,n)=f(m-1,n)+f(m-n,n)(所有盘子都有和有空的)

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  • 原文地址:https://www.cnblogs.com/ningwei/p/poj1664.html
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