需求:
sql语句中,判断以逗号分隔的字符串中是否包含某个特定字符串,类似于判断一个数组中是否包含某一个元素,
例如:判断 ’a,b,c,d,e,f,g‘ 中是否包含 'a',sql语句如何实现?
解决
1、mysql 字符串函数判断: FIND_IN_SET(ele, str)
ele 是一个特定字符,
str 是一个以逗号分隔的字符串 或者 匹配这个参数的字段,必须以逗号分隔
select * from t_user where FIND_IN_SET('26', '1,26');
//ids: 以逗号分割的字符串
select * from t_user where FIND_IN_SET('26', ids);
FIND_IN_SET() 函数返回该字符串所在的位置,如果不存在就返回0,
2、ORDER BY FIND_IN_SET() 可以用来排序。
如果想让 id 按 30 27 29 排序
select * from t_user where id in(30,27,29) order by FIND_IN_SET(id,'30,29,27');
二 原文
I have a many-to-many relationship between People and Departments since one person can be in many departments.
People Departments ------ ----------- pID pName deptID deptName 1 James 1 Engineering 2 Mary 2 Research 3 Paul 3 Marketing 4 Communications People_Departments ------------------ pID deptID 1 1 1 2 2 2 2 4 3 1 3 2 3 3
What I want is this:
pName deptName James Engineering, Research Mary Research, Communication Paul Engineering, Research, Marketing
If I do plain LEFT JOINs on the tables using the SQL below, I will get several rows related to one person:
SELECT people.pName, departments.deptName FROM people LEFT JOIN people_departments ON people.pID=people_departments.pID LEFT JOIN departments ON people_departments.deptID=departments.deptID
I have tried various combinations of GROUP_CONCAT but without luck.
Any ideas to share?
解决
SELECT people.pName, GROUP_CONCAT(departments.deptName SEPARATOR ', ') deptName FROM people LEFT JOIN people_departments ON people.pID = people_departments.pID INNER JOIN departments ON people_departments.deptID = departments.deptID GROUP BY people.pID
Output:
+-------+----------------------------------+ | pName | deptName | +-------+----------------------------------+ | James | Engineering, Research | | Mary | Research, Communications | | Paul | Engineering, Research, Marketing | +-------+----------------------------------+ 3 rows in set (0.00 sec)
(转载https://blog.csdn.net/qq_42402854/article/details/88030469 && https://www.it1352.com/1475016.html)