静态加载问题

阿里笔试题

连接：http://blog.csdn.net/geekdonie/article/details/12260599

public class Test {

    public static int k = 0;
    public static Test t1 = new Test("t1");
    public static Test t2 = new Test("t2");
    public static int i = print("i");
    public static int n = 99;
    private int a = 0;
    public int j = print("j");
    {
        print("构造块");
    }
    static {
        print("静态块");
    }

    public Test(String str) {
        System.out.println((++k) + ":" + str + "   i=" + i + "    n=" + n);
        ++i;
        ++n;
    }

    public static int print(String str) {
        System.out.println((++k) + ":" + str + "   i=" + i + "    n=" + n);
        ++n;
        return ++i;
    }

    public static void main(String args[]) {
        Test t = new Test("init");
    }

}

结果输出：

1:j   i=0    n=0
2:构造块   i=1    n=1
3:t1   i=2    n=2
4:j   i=3    n=3
5:构造块   i=4    n=4
6:t2   i=5    n=5
7:i   i=6    n=6
8:静态块   i=7    n=99
9:j   i=8    n=100
10:构造块   i=9    n=101
11:init   i=10    n=102

笔试题2：

public class Test {

    static {
        int x = 5;
    }
    
    static int x, y;
    public static void main(String[] args) {
        
        x--;
        myMethod();
        System.out.println(x + y++ + x);
    }
    
    public static void myMethod(){
        y = x++ + ++x;
    }
}

输出：2