1. 最佳选择：利用分析函数
row_number() over ( partition by col1 order by col2 )
比如想取出100-150条记录,按照tname排序
select tname,tabtype from (
select tname,tabtype,row_number() over ( order by tname ) rn from tab
)
where rn between 100 and 150;
2. 使用rownum 虚列
select tname,tabtype from (
select tname,tabtype,rownum rn from tab where rownum <= 150
)
where rn >= 100;
注释：使用序列时不能基于整个记录集合来进行排序,假如指定了order by子句,排序的的是选出来的记录集的排序。
在ORACLE如果想取一张表按时间排序后的前5条最新记录: 方法一\二对,方法三错
SELECT GUID,title,content FROM
(SELECT GUID,title,content, row_number() over (order by releasetime desc)tm
FROM web_LO_Article WHERE funID=20 and content like '%<img %')
WHERE tm between 1 and 5
或者:select * from (select * from web_LO_Article where funID=20 and content like '%<img %' order by releasetime desc)where rownum<6
ROW_NUMBER() 就是生成一个顺序的行号,而他生成顺序的标准,就是后面紧跟的OVER(ORDER BY ReportID)
SELECT GUID,title,content,releaseTime
FROM web_LO_Article
WHERE funID=20 and rownum<6 and content like '%<img %' order by releaseTime desc
方法三表示:查询数据库中的前5条数据，然后在对它们按时间降序排列。