• Java产生死锁的一个简单例子


    思路是创建两个字符串a和b,再创建两个线程A和B,让每个线程都用synchronized锁住字符串(A先锁a,再去锁b;B先锁b,再锁a),如果A锁住a,B锁住b,A就没办法锁住b,B也没办法锁住a,这时就陷入了死锁。直接贴代码:

    public class DeadLock {
        public static String obj1 = "obj1";
        public static String obj2 = "obj2";
        public static void main(String[] args){
            Thread a = new Thread(new Lock1());
            Thread b = new Thread(new Lock2());
            a.start();
            b.start();
        }    
    }
    class Lock1 implements Runnable{
        @Override
        public void run(){
            try{
                System.out.println("Lock1 running");
                while(true){
                    synchronized(DeadLock.obj1){
                        System.out.println("Lock1 lock obj1");
                        Thread.sleep(3000);//获取obj1后先等一会儿,让Lock2有足够的时间锁住obj2
                        synchronized(DeadLock.obj2){
                            System.out.println("Lock1 lock obj2");
                        }
                    }
                }
            }catch(Exception e){
                e.printStackTrace();
            }
        }
    }
    class Lock2 implements Runnable{
        @Override
        public void run(){
            try{
                System.out.println("Lock2 running");
                while(true){
                    synchronized(DeadLock.obj2){
                        System.out.println("Lock2 lock obj2");
                        Thread.sleep(3000);
                        synchronized(DeadLock.obj1){
                            System.out.println("Lock2 lock obj1");
                        }
                    }
                }
            }catch(Exception e){
                e.printStackTrace();
            }
        }
    }

    运行的结果如图所示:

    可以看到,Lock1获取obj1,Lock2获取obj2,但是它们都没有办法再获取另外一个obj,因为它们都在等待对方先释放锁,这时就是死锁。

    如果我们只运行Lock1呢?修改一下main函数,把线程b注释掉。

    public class DeadLock {
        public static String obj1 = "obj1";
        public static String obj2 = "obj2";
        public static void main(String[] args){
            Thread a = new Thread(new Lock1());
            //Thread b = new Thread(new Lock2());
            a.start();
            //b.start();
        }
    }
    class Lock1 implements Runnable{
        @Override
        public void run(){
            try{
                System.out.println("Lock1 running");
                while(true){
                    synchronized(DeadLock.obj1){
                        System.out.println("Lock1 lock obj1");
                        Thread.sleep(3000);
                        synchronized(DeadLock.obj2){
                            System.out.println("Lock1 lock obj2");
                        }
                    }
                }
            }catch(Exception e){
                e.printStackTrace();
            }
        }
    }
    class Lock2 implements Runnable{
        @Override
        public void run(){
            try{
                System.out.println("Lock2 running");
                while(true){
                    synchronized(DeadLock.obj2){
                        System.out.println("Lock2 lock obj2");
                        Thread.sleep(3000);
                        synchronized(DeadLock.obj1){
                            System.out.println("Lock2 lock obj1");
                        }
                    }
                }
            }catch(Exception e){
                e.printStackTrace();
            }
        }
    }

    运行结果为:

    由于没有其它线程和Lock1争夺obj1和obj2,Lock1可以不断地循环获取并释放它们,这时没有死锁。

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  • 原文地址:https://www.cnblogs.com/mudao/p/5867107.html
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