Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; class Solution { public: TreeNode *sortedArrayToBST(std::vector<int> &num) { return ArrayToBST(num,0,num.size()-1); } private: TreeNode *ArrayToBST(std::vector<int> &num, int start, int end) { if(start > end) return NULL; int mid = (start + end) / 2; TreeNode *root = new TreeNode(num[mid]); root->left = ArrayToBST(num,start,mid - 1); root->right = ArrayToBST(num,mid + 1, end); return root; } };