• Opencv-Python 图像透视变换cv2.warpPerspective


    # -*- coding:utf-8 -*-
    import cv2
    import numpy as np
    import sys
    
    img = cv2.imread('test.jpg')
    # cv2.imshow("original", img)
    
    # 可选,扩展图像,保证内容不超出可视范围
    img = cv2.copyMakeBorder(img, 200, 200, 200, 200, cv2.BORDER_CONSTANT, 0)
    w, h = img.shape[0:2]
    
    anglex = 0
    angley = 30
    anglez = 0  # 是旋转
    fov = 42
    r = 0
    
    def rad(x):
        return x * np.pi / 180
    
    def get_warpR():
        global anglex,angley,anglez,fov,w,h,r
        # 镜头与图像间的距离,21为半可视角,算z的距离是为了保证在此可视角度下恰好显示整幅图像
        z = np.sqrt(w ** 2 + h ** 2) / 2 / np.tan(rad(fov / 2))
        # 齐次变换矩阵
        rx = np.array([[1, 0, 0, 0],
                       [0, np.cos(rad(anglex)), -np.sin(rad(anglex)), 0],
                       [0, -np.sin(rad(anglex)), np.cos(rad(anglex)), 0, ],
                       [0, 0, 0, 1]], np.float32)
    
        ry = np.array([[np.cos(rad(angley)), 0, np.sin(rad(angley)), 0],
                       [0, 1, 0, 0],
                       [-np.sin(rad(angley)), 0, np.cos(rad(angley)), 0, ],
                       [0, 0, 0, 1]], np.float32)
    
        rz = np.array([[np.cos(rad(anglez)), np.sin(rad(anglez)), 0, 0],
                       [-np.sin(rad(anglez)), np.cos(rad(anglez)), 0, 0],
                       [0, 0, 1, 0],
                       [0, 0, 0, 1]], np.float32)
    
        r = rx.dot(ry).dot(rz)
    
        # 四对点的生成
        pcenter = np.array([h / 2, w / 2, 0, 0], np.float32)
    
        p1 = np.array([0, 0, 0, 0], np.float32) - pcenter
        p2 = np.array([w, 0, 0, 0], np.float32) - pcenter
        p3 = np.array([0, h, 0, 0], np.float32) - pcenter
        p4 = np.array([w, h, 0, 0], np.float32) - pcenter
    
        dst1 = r.dot(p1)
        dst2 = r.dot(p2)
        dst3 = r.dot(p3)
        dst4 = r.dot(p4)
    
        list_dst = [dst1, dst2, dst3, dst4]
    
        org = np.array([[0, 0],
                        [w, 0],
                        [0, h],
                        [w, h]], np.float32)
    
        dst = np.zeros((4, 2), np.float32)
    
        # 投影至成像平面
        for i in range(4):
            dst[i, 0] = list_dst[i][0] * z / (z - list_dst[i][2]) + pcenter[0]
            dst[i, 1] = list_dst[i][1] * z / (z - list_dst[i][2]) + pcenter[1]
    
        warpR = cv2.getPerspectiveTransform(org, dst)
        return warpR
    
    def control():
        global anglex,angley,anglez,fov,r
    
        # 键盘控制
        if 27 == c:  # Esc quit
            sys.exit()
        if c == ord('w'):
            anglex += 1
        if c == ord('s'):
            anglex -= 1
        if c == ord('a'):
            angley += 1
            print(angley)
            # dx=0
        if c == ord('d'):
            angley -= 1
        if c == ord('u'):
            anglez += 1
        if c == ord('p'):
            anglez -= 1
        if c == ord('t'):
            fov += 1
        if c == ord('r'):
            fov -= 1
        if c == ord(' '):
            anglex = angley = anglez = 0
        if c == ord('e'):
            print("======================================")
            print('Rotation Matrix:')
            print(r)
            print('angle alpha(anglex):')
            print(anglex)
            print('angle beta(angley):')
            print(angley)
            print('dz(anglez):')
            print(anglez)
    
    
    while True:
    
        warpR = get_warpR()
    
        result = cv2.warpPerspective(img, warpR, (h, w))
        cv2.namedWindow('result',2)
        cv2.imshow("result", result)
        c = cv2.waitKey(30)
        control()
    
    cv2.destroyAllWindows()


    运行效果:


    控制:

    • s控制垂直方向上的形变
    • a和d控制水平方向上的行变
    • u和p控制角度旋转
    • e 输出当前旋转矩阵参数
  • 相关阅读:
    C/C++编译过程
    Struts2入门01
    NET CORE 微软官方说明链接
    PL/SQL控制语句(二、循环控制语句)
    PL/SQL控制语句(一、分支控制语句)
    PL/SQL数据类型
    PL/SQL变量的作用域和可见性
    PL/SQL变量和类型
    CopyWebpackPlugin 的使用
    flex
  • 原文地址:https://www.cnblogs.com/mtcnn/p/9411687.html
Copyright © 2020-2023  润新知