• 数组问题


    1.数组越界和求和溢出

     1 //作者:王炳午  董龙洋  日期:2015.3.28
     2 #include<iostream.h>
     3 #include<stdlib.h>
     4 #include<time.h>
     5 int main()
     6 {
     7     cout<<"---------------------求数组中子数组和的最大值的小程序----------------------"<<endl;
     8     cout<<endl;
     9     signed long int a[1000];
    10     int i;
    11     int j;
    12     srand( (unsigned)time( NULL ) );//随机数种子为当前计算机时间。
    13     cout<<"得到的一组随机整数(1000个数)如下:"<<endl;
    14     /*a[0]=2147483647;
    15     cout<<a[0]<<"	";*/
    16     for(i=0;i<1000;i++)
    17     {
    18      //随机生成长整型整数
    19         j=rand()%2;
    20         if(j==0)
    21         {
    22             a[i]=rand()%2147483648;
    23         }
    24         else
    25         {
    26             a[i]=0-rand()%2147483648;
    27         }
    28         cout<<a[i]<<"	";
    29     }
    30     cout<<endl;
    31     int sum=0;  
    32     int GreateSum=0;  
    33     for ( i=0;i<1000;i++)  
    34     {  
    35         //防止最大值溢出
    36         if(sum>2147483647)
    37         {
    38             sum=2147483647;
    39         }
    40         sum+=a[i];  
    41         if (sum<0)  
    42         {  
    43             sum=0;  
    44         }  
    45         if (sum>GreateSum)  
    46         {  
    47             GreateSum=sum;  
    48         }
    49         //防止最大值溢出
    50         if(GreateSum>2147483647)
    51         {
    52             GreateSum=2147483647;
    53 
    54         }
    55     }  
    56     if (GreateSum==0)  
    57     {  
    58         for (int i=0;i<1000;i++)  
    59         {  
    60             if (GreateSum==0)  
    61             {  
    62                 GreateSum=a[i];  
    63             }  
    64             else  
    65             if (GreateSum<a[i])  
    66             {  
    67                 GreateSum=a[i];  
    68             }  
    69         }  
    70     }  
    71     cout<<"最大值sum:"<<GreateSum<<endl;  
    72     system("pause");  
    73     return 0;  
    74 }  

    2.环形数组最大值
      1 #include<iostream.h>
      2 #include<stdlib.h>
      3 #include<time.h>
      4 int main()
      5 {
      6     cout<<"---------------------求数组中子数组和的最大值的小程序----------------------"<<endl;
      7     cout<<endl;
      8     int a[5];
      9     int c[5];
     10     int b[10];
     11     int i;
     12     srand( (unsigned)time( NULL ) );//随机数种子为当前计算机时间。
     13     for(i=0;i<5;i++)
     14     {
     15         a[i]=rand()%22-11;//得到一组-10到10的整数;
     16         cout<<a[i]<<"	";
     17     }
     18     cout<<endl;
     19     for(i=0;i<9;i++)
     20     { 
     21         if(i<5)
     22             b[i]=a[i];
     23         else
     24             b[i]=a[i-5];
     25     //cout<<b[i]<<"	";
     26     }
     27     cout<<endl;
     28     //最大值求法
     29     int sum=0;  
     30     int GreateSum=0; 
     31     //1-5
     32     for ( i=0;i<5;i++)  
     33     {  
     34         sum+=b[i];  
     35         if (sum<0)  
     36         {  
     37             sum=0;  
     38         }  
     39         if (sum>GreateSum)  
     40         {  
     41             GreateSum=sum; 
     42         }
     43     }  
     44     if (GreateSum==0)  
     45     {  
     46         for (int i=0;i<5;i++)  
     47         {  
     48             if (GreateSum==0)  
     49             {  
     50                 GreateSum=b[i];  
     51             }  
     52             else  
     53                 if (GreateSum<b[i])  
     54                 {  
     55                     GreateSum=b[i];
     56                 }  
     57         }  
     58     }
     59     c[0]=GreateSum;
     60     //2-6
     61     sum=0;  
     62     GreateSum=0; 
     63     for ( i=1;i<6;i++)  
     64     {  
     65         sum+=b[i];  
     66         if (sum<0)  
     67         {  
     68             sum=0;  
     69         }  
     70         if (sum>GreateSum)  
     71         {  
     72             GreateSum=sum;  
     73         }
     74     }  
     75     if (GreateSum==0)  
     76     {  
     77         for (int i=1;i<6;i++)  
     78         {  
     79             if (GreateSum==0)  
     80             {  
     81                 GreateSum=b[i];  
     82             }  
     83             else  
     84                 if (GreateSum<b[i])  
     85                 {  
     86                     GreateSum=b[i];  
     87                 }  
     88         }  
     89     }
     90     c[1]=GreateSum;
     91     //3-7
     92     sum=0;  
     93     GreateSum=0; 
     94     for ( i=2;i<7;i++)  
     95     {  
     96         sum+=b[i];  
     97         if (sum<0)  
     98         {  
     99             sum=0;  
    100         }  
    101         if (sum>GreateSum)  
    102         {  
    103             GreateSum=sum;  
    104         }
    105     }  
    106     if (GreateSum==0)  
    107     {  
    108         for (int i=2;i<7;i++)  
    109         {  
    110             if (GreateSum==0)  
    111             {  
    112                 GreateSum=b[i];  
    113             }  
    114             else  
    115                 if (GreateSum<b[i])  
    116                 {  
    117                     GreateSum=b[i];  
    118                 }  
    119         }  
    120     }
    121     c[2]=GreateSum;
    122     //4-8
    123     sum=0;  
    124     GreateSum=0; 
    125     for ( i=3;i<8;i++)  
    126     {  
    127         sum+=b[i];  
    128         if (sum<0)  
    129         {  
    130             sum=0;  
    131         }  
    132         if (sum>GreateSum)  
    133         {  
    134             GreateSum=sum;  
    135         }
    136     }  
    137     if (GreateSum==0)  
    138     {  
    139         for (int i=3;i<8;i++)  
    140         {  
    141             if (GreateSum==0)  
    142             {  
    143                 GreateSum=b[i];  
    144             }  
    145             else  
    146                 if (GreateSum<b[i])  
    147                 {  
    148                     GreateSum=b[i];  
    149                 }  
    150         }  
    151     }
    152     c[3]=GreateSum;
    153     //5-9
    154     sum=0;  
    155     GreateSum=0; 
    156     for ( i=4;i<9;i++)  
    157     {  
    158         sum+=b[i];  
    159         if (sum<0)  
    160         {  
    161             sum=0;  
    162         }  
    163         if (sum>GreateSum)  
    164         {  
    165             GreateSum=sum;  
    166         }
    167     }  
    168     if (GreateSum==0)  
    169     {  
    170         for (int i=4;i<9;i++)  
    171         {  
    172             if (GreateSum==0)  
    173             {  
    174                 GreateSum=b[i];  
    175             }  
    176             else  
    177                 if (GreateSum<b[i])  
    178                 {  
    179                     GreateSum=b[i];  
    180                 }  
    181         }  
    182     }
    183     c[4]=GreateSum;
    184     for(i=0;i<5;i++)
    185     {
    186         //cout<<c[i]<<"	";
    187         if(GreateSum<c[i])
    188         {
    189             GreateSum=c[i];
    190         }
    191     }
    192     cout<<endl;
    193     cout<<"最大子数组和的值为:"<<GreateSum<<endl;
    194     return 0;
    195 }

    总结:本次试验我收获颇多,在本次试验我充当了导航员的角色,结合前面的几次试验我对结对开发好感很多,1+1>大于2,不管是前期的构思还是中期的代码书写其中又包含了很多,比如代码的书写规范和一些小的算法或者小的技巧,一个给力的小伙伴让我不想学习时也会激励我。当然我们也遇到了很多问题一起解决一起面对,即使解决不了也能乐观一点,互相开开玩笑。

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  • 原文地址:https://www.cnblogs.com/mtant/p/4378254.html
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