Path Sum

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
             / 
            4   8
           /   / 
          11  13  4
         /        
        7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

深度遍历解决，中序遍历代码如下：

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    
    //深度遍历二叉树
    public boolean DFS(TreeNode node,int sum,int currentSum) {
        if(node==null) return false;
        if(node.left==null&&node.right==null) return (currentSum+node.val)==sum;
        else{
            return DFS(node.left,sum,currentSum+node.val)||DFS(node.right,sum,currentSum+node.val);
        }
    }
    
    public boolean hasPathSum(TreeNode root, int sum) {
        return DFS(root,sum,0);
    }
}