• [国家集训队]小Z的袜子


    嘟嘟嘟


    一眼就知道是莫队。


    还不带修改,美滋滋。
    按莫队的方法排序,然后用小学数学算一下概率,分子分母单独维护。

    #include<cstdio>
    #include<iostream>
    #include<cmath>
    #include<algorithm>
    #include<cstring>
    #include<cstdlib>
    #include<cctype>
    #include<vector>
    #include<stack>
    #include<queue>
    using namespace std;
    #define enter puts("") 
    #define space putchar(' ')
    #define Mem(a, x) memset(a, x, sizeof(a))
    #define rg register
    typedef long long ll;
    typedef double db;
    const int INF = 0x3f3f3f3f;
    const db eps = 1e-8;
    const int maxn = 5e4 + 5;
    inline ll read()
    {
      ll ans = 0;
      char ch = getchar(), last = ' ';
      while(!isdigit(ch)) last = ch, ch = getchar();
      while(isdigit(ch)) ans = (ans << 1) + (ans << 3) + ch - '0', ch = getchar();
      if(last == '-') ans = -ans;
      return ans;
    }
    inline void write(ll x)
    {
      if(x < 0) x = -x, putchar('-');
      if(x >= 10) write(x / 10);
      putchar(x % 10 + '0');
    }
    
    int n, m, S, a[maxn];
    int cnt = 0, tot[maxn];
    #define bel(x) (((x) - 1) / S + 1)
    struct Node
    {
      int L, R, id;
      bool operator < (const Node& oth)const
      {
        return bel(L) < bel(oth.L) || (bel(L) == bel(oth.L) && R < oth.R);
      }
    }q[maxn];
    struct Ans
    {
      ll x, y;
    }ans[maxn];
    
    inline ll gcd(ll a, ll b) {return b ? gcd(b, a % b) : a;}
    
    inline void add(int x)
    {
      cnt += (tot[x] << 1);
      tot[x]++;
    }
    inline void del(int x)
    {
      cnt -= ((tot[x] - 1) << 1);
      tot[x]--;
    }
    
    int main()
    {
      n = read(); m = read(); S = sqrt(n);
      for(int i = 1; i <= n; ++i) a[i] = read();
      for(int i = 1; i <= m; ++i) q[i].L = read(), q[i].R = read(), q[i].id = i;
      sort(q + 1, q + m + 1);
      int l = 1, r = 0;
      for(int i = 1; i <= m; ++i)
        {
          while(l < q[i].L) del(a[l++]);
          while(l > q[i].L) add(a[--l]);
          while(r < q[i].R) add(a[++r]);
          while(r > q[i].R) del(a[r--]);
          if(!cnt) ans[q[i].id] = (Ans){0, 1};
          else
    	{
    	  ll len = q[i].R - q[i].L + 1, d = gcd(cnt, (ll)len * (ll)(len - 1));
    	  ans[q[i].id] = (Ans){cnt / d, (ll)len * (len - 1) / d};
    	}
        }
      for(int i = 1; i <= m; ++i) write(ans[i].x), putchar('/'), write(ans[i].y), enter;
      return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/mrclr/p/10077550.html
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