• 1083 List Grades (25)


    Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

    Input Specification:

    Each input file contains one test case. Each case is given in the following format:

    N
    name[1] ID[1] grade[1]
    name[2] ID[2] grade[2]
    ... ...
    name[N] ID[N] grade[N]
    grade1 grade2
    

    where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

    Output Specification:

    For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output "NONE" instead.

    Sample Input 1:

    4
    Tom CS000001 59
    Joe Math990112 89
    Mike CS991301 100
    Mary EE990830 95
    60 100
    

    Sample Output 1:

    Mike CS991301
    Mary EE990830
    Joe Math990112
    

    Sample Input 2:

    2
    Jean AA980920 60
    Ann CS01 80
    90 95
    

    Sample Output 2:

    NONE

     1 #include<iostream>
     2 #include<vector>
     3 #include<algorithm>
     4 using namespace std;
     5 struct node{
     6   char name[15], id[15];
     7   int score;
     8 };
     9 
    10 bool cmp(node a, node b){return a.score>b.score;}
    11 int main(){
    12   int n, i;
    13   scanf("%d", &n);
    14   vector<node> v(n);
    15   for(i=0; i<n; i++) scanf("%s %s %d", v[i].name, v[i].id, &v[i].score);
    16   int maxx, minn;
    17   scanf("%d%d", &minn, &maxx);
    18   bool f = true;
    19   sort(v.begin(), v.end(), cmp);
    20   for(i=0; i<n; i++){
    21     if(minn<=v[i].score && maxx>=v[i].score){
    22       printf("%s %s
    ", v[i].name, v[i].id); 
    23       f=false;
    24     }else if(!f) break;
    25   }
    26   if(f) printf("NONE
    ");
    27   return 0;
    28 }
    有疑惑或者更好的解决方法的朋友,可以联系我,大家一起探讨。qq:1546431565
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  • 原文地址:https://www.cnblogs.com/mr-stn/p/9163897.html
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