今天在网上看到一个使用html实现的动态鲜花的页面，感觉很有意思，先保存下来！
先看效果图：
直接上代码：
<html> <head><meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>The rose for MIAO</title> </head> <body style="background-color: #8EC5FC; background-image: linear-gradient(62deg, #8EC5FC 0%, #E0C3FC 100%);"> <h1> <p style="margin-left: 180px;color: purple;font-family: 微软雅黑">I Love You!</p> </h1> <canvas id="c" height="613" width="613"></canvas> <script> var b = document.body; var c = document.getElementsByTagName('canvas')[0]; var a = c.getContext('2d'); document.body.clientWidth; </script> <script> with (m = Math) C = cos, S = sin, P = pow, R = random; c.width = c.height = f = 613; h = -250; function p(a, b, c) { if (c > 60) return [ S(a * 7) * (13 + 5 / (.2 + P(b * 4, 4))) - S(b) * 50, b * f + 50, 625 + C(a * 7) * (13 + 5 / (.2 + P(b * 4, 4))) + b * 400, a * 1 - b / 2, a ]; A = a * 2 - 1; B = b * 2 - 1; if(A*A+B*B<1){if(c>37){n=(j=c&1)?6:4;o=.5/(a+.01)+C(b*125)*3-a*300;w=b*h;return[o*C(n)+w*S(n)+j*610-390,o*S(n)-w*C(n)+550-j*350,1180+C(B+A)*99-j*300,.4-a*.1+P(1-B*B,-h*6)*.15-a*b*.4+C(a+b)/5+P(C((o*(a+1)+(B>0?w:-w))/25),30)*.1*(1-B*B),o/1e3+.7-o*w*3e-6]}if(c>32){c=c*1.16-.15;o=a*45-20;w=b*b*h;z=o*S(c)+w*C(c)+620;return[o*C(c)-w*S(c),28+C(B*.5)*99-b*b*b*60-z/2-h,z,(b*b*.3+P((1-(A*A)),7)*.15+.3)*b,b*.7]}o=A*(2-b)*(80-c*2);w=99-C(A)*120-C(b)*(-h-c*4.9)+C(P(1-b,7))*50+c*2;z=o*S(c)+w*C(c)+700;return[o*C(c)-w*S(c),B*99-C(P(b, 7))*50-c/3-z/1.35+450,z,(1-b/1.2)*.9+a*.1, P((1-b),20)/4+.05]}}setInterval('for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',0) </script> <script> (function() { var ws = new WebSocket('ws://' + window.location.host + '/jb-server-page?reloadServiceClientId=39'); ws.onmessage = function (msg) { if (msg.data === 'reload') { window.location.reload(); } if (msg.data.startsWith('update-css ')) { var messageId = msg.data.substring(11); var links = document.getElementsByTagName('link'); for (var i = 0; i < links.length; i++) { var link = links[i]; if (link.rel !== 'stylesheet') continue; var clonedLink = link.cloneNode(true); var newHref = link.href.replace(/(&|\?)jbUpdateLinksId=\d+/, "$1jbUpdateLinksId=" + messageId); if (newHref !== link.href) { clonedLink.href = newHref; } else { var indexOfQuest = newHref.indexOf('?'); if (indexOfQuest >= 0) { clonedLink.href = newHref.substring(0, indexOfQuest + 1) + 'jbUpdateLinksId=' + messageId + '&' + newHref.substring(indexOfQuest + 1); } else { clonedLink.href += '?' + 'jbUpdateLinksId=' + messageId; } } link.replaceWith(clonedLink); } } }; })(); </script> </body> </html>
出处：https://www.cnblogs.com/wydilearn/p/15910970.html
