1.链接地址:
http://bailian.openjudge.cn/practice/1163
http://poj.org/problem?id=1163
2.题目:
- 总时间限制:
- 1000ms
- 内存限制:
- 65536kB
- 描述
7
3 8
8 1 0
2 7 4 4
4 5 2 6 5
(Figure 1)
Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right.- 输入
- Your program is to read from standard input. The first line contains one integer N: the number of rows in the triangle. The following N lines describe the data of the triangle. The number of rows in the triangle is > 1 but <= 100. The numbers in the triangle, all integers, are between 0 and 99.
- 输出
- Your program is to write to standard output. The highest sum is written as an integer.
- 样例输入
5 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5- 样例输出
30- 来源
- IOI 1994
3.思路:
DP
4.代码:
1 #include "stdio.h" 2 //#include "stdlib.h" 3 #define N 102 4 int a[N][N]; 5 int main() 6 { 7 int count; 8 int i,j; 9 scanf("%d",&count); 10 for(i = 0 ;i <count;i++) 11 { 12 for(j=0;j<=i;j++) 13 { 14 scanf("%d",&a[i][j]); 15 } 16 } 17 for(i = count -2;i>=0;i--) 18 { 19 for(j=0;j<=i;j++) 20 { 21 a[i][j] += ((a[i+1][j]>a[i+1][j+1])?a[i+1][j]:a[i+1][j+1]); 22 } 23 } 24 printf("%d",a[0][0]); 25 //system("pause"); 26 return 1; 27 }