• (easy)LeetCode 225.Implement Stack using Queues


    Implement the following operations of a stack using queues.

    • push(x) -- Push element x onto stack.
    • pop() -- Removes the element on top of the stack.
    • top() -- Get the top element.
    • empty() -- Return whether the stack is empty.

    Notes:

    • You must use only standard operations of a queue -- which means only push to backpeek/pop from frontsize, and is empty operations are valid.
    • Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
    • You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).

    Update (2015-06-11):
    The class name of the Java function had been updated to MyStack instead of Stack.

    Credits:
    Special thanks to @jianchao.li.fighter for adding this problem and all test cases.

    解析:java 中,Queue接口可使用的函数有 offer(E e):添加到队列尾  peek():查看队列头  poll():删除队头元素 remove()移除队头元素

             另外:Deque接口中的push(),pop()操作均是在队头操作。

    代码如下:

    class MyStack {
        // Push element x onto stack.
        Queue<Integer> q1=new LinkedList<Integer>();
        Queue<Integer> q2=new LinkedList<Integer>();
        
        public void push(int x) {
            q1.offer(x);
        }
    
        // Removes the element on top of the stack.
        public void pop() {
            while(q1.size()>1) q2.offer(q1.poll());
            q1.poll();
            Queue<Integer> q=q1;
            q1=q2;
            q2=q;
            
        }
    
        // Get the top element.
        public int top() {
          while(q1.size()>1) q2.offer(q1.poll());
          int x=q1.poll();
          q2.offer(x);
          Queue<Integer>q=q1;
          q1=q2;
          q2=q;
          return x;
        }
    
        // Return whether the stack is empty.
        public boolean empty() {
            return q1.isEmpty();
        }
    }
    

      运行结果:

          

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  • 原文地址:https://www.cnblogs.com/mlz-2019/p/4690492.html
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