偶数求和

#include <cstdio>

int main()
{
	int n, m;
	while(scanf("%d %d", &n, &m) != EOF)
	{
		int sum = 0, count = 0;
		for(int i = 2; i <= 2*n; i += 2)
		{
			sum += i;
			if((i/2) % m == 0)
			{
				count ++;
				if(count == 1)	printf("%d", sum / m);
				else	printf(" %d", sum / m);
				sum = 0;
			}
		}
//		printf("sum = %d
", sum);
		if(sum != 0)
		{
			printf(" %d", sum / (n % m));
		}
		printf("
");
	}
	
	return 0;
}