#include <iostream> #include <vector> #include <string> #include <queue> #include <cassert> using namespace std; template<typename Key, typename Value> class BST { public : BST() { root = NULL; count = 0; } ~BST() { // TODO : ~BST() destroy(root); } int size() { return count; } bool isEmpty() { return count == 0; } // 插入结点 void insert(Key key, Value value) { root = insert(root, key, value); } // 是否包含该键值的结点 bool contain(Key key) { return contain(root, key); } // 返回值为指针类型: 若未查找到, 返回空 // 若查找到, 返回指向value地址的指针 Value * search(Key key) { return search(root, key); } //前序遍历 void preOrder() { preOrder(root); } // 中序遍历 void inOrder() { inOrder(root); } // 后序遍历 void postOrder() { postOrder(root); } // 层序遍历 void levelOrder() { queue<Node*> q; q.push(root); while(!q.empty()) { Node * node = q.front(); q.pop(); cout << node->key << endl; if(node->left) q.push(node->left); if(node->right) q.push(node->right); } } // 寻找最小的键值 Key minimum() { assert(count != 0); Node * minNode = minimum(root); return minNode->key; } // 寻找最大的键值 Key maximum() { assert(count != 0); Node * maxNode = maximum(root); return maxNode->key; } // 从二叉树中删除最小值所在节点 void removeMin() { if(root) root = removeMin(root); } // 从二叉树中删除最大值所在的结点 void removeMax() { if(root) root = removeMax(root); } // 从二叉树中删除键值为key的结点 void remove(Key key) { root = remove(root, key); } private : struct Node { Key key; Value value; Node * left; Node * right; Node(Key key, Value value) { this->key = key; this->value = value; this->left = this->right = NULL; } Node(Node *node) { this->key = node->key; this->value = node->value; this->left = node->left; this->right = node->right; } }; Node * root; int count; // 二分搜索树的节点个数 Node * insert(Node * node, Key key, Value value) { if(node == NULL) { count ++; return new Node(key, value); } if(key == node->key) node->value = value; else if(key < node->key) node->left = insert(node->left, key, value); else node->right = insert(node->right, key, value); return node; } bool contain(Node * node, Key key) { if(node == NULL) return false; if(key == node->key) return true; else if(key < node->key) return contain(node->left, key); else return contain(node->right, key); } // 在以node为根的二叉搜索树中查找key所对应的value Value * search(Node * node, Key key) { if(node == NULL) return NULL; if(key == node->key) return &(node->value); else if(key < node->key) return search(node->left, key); else return search(node->right, key); } void preOrder(Node * node) { if(node != NULL) { cout << node->key << endl; preOrder(node->left); preOrder(node->right); } return ; } void inOrder(Node * node) { if(node != NULL) { inOrder(node->left); cout << node->key << endl; inOrder(node->right); } return ; } void postOrder(Node * node) { if(node != NULL) { postOrder(node->left); postOrder(node->right); cout << node->key << endl; } return ; } void destroy(Node * node) { // 先删除左子树, 再删除右子树, 最后删除根节点 if(node != NULL) { destroy(node->left); destroy(node->right); delete node; count --; } } // 在以node为根的二叉搜索树中, 返回最小键值的结点 Node * minimum(Node * node) { if(node->left == NULL) return node; return minumum(node->left); } // 在以node为根的二叉搜索树中, 返回最大键值的结点 Node maximum(Node * node) { if(node->right == NULL) return node; return maximum(node->right); } // 删除以node为根的二分搜索树中的最小节点 // 返回删除结点后的新的二分搜索树的根 Node * removeMin(Node * node) { if(node->left == NULL) { Node * rightNode = node->right; delete node; count --; return rightNode; } node->left = removeMin(node->left); return node; } // 删除以node为根的二分搜索树中的最大节点 // 返回删除结点后的新的二分搜索树的根 Node * removeMax(Node * node) { if(node->right == NULL) { Node * leftNode = node->left; delete node; count --; return leftNode; } node->right = removeMax(node->right); return node; } // 删除以node为根的二分搜索树中键值为key的结点 // 返回删除结点后的二分搜索树的根 Node * remove(Node * node, Key key) { if(node == NULL) return NULL; if(key < node->key) { node->left = remove(node->left, key); return node; } else if(key > node->key) { node->right = remove(node->right, key); return node; } else { // key == node->key if(node->left == NULL) { Node * rightNode = node->right; delete node; count --; return rightNode; } if(node->right == NULL) { Node * leftNode = node->left; delete node; count --; return leftNode; } // node->left != NULL && node->right != NULL Node * successor = new Node(minimum(node->right)); count ++; successor->right = removeMin(node->right); successor->left = node->left; delete node; count --; return successor; } } };