• mysql 数据操作 单表查询 where约束 between and or


    WHERE约束

    where字句中可以使用:

      1. 比较运算符:>< >=  <=  !=
      2. between 80 and 100 值在80到100之间   >=80  <=100
      3. in(80,90,100) 值是80或90或100    满足这个条件就可以
      4. like 'egon%'
        pattern可以是%或_,
        %表示任意多字符
        _表示一个字符
      5. 逻辑运算符:在多个条件直接可以使用逻辑运算符 and or not

     

    select id,name,age from employee where id >7;

    执行顺序 1.from employee  2. where id >7 3. id,name,age

    先找到表 再按照约束条件 从表里取要找的记录

    单个条件

    mysql> select id,name,age from employee where id >7;
    +----+-----------+-----+
    | id | name      | age |
    +----+-----------+-----+
    |  8 | 丫丫      |  38 |
    |  9 | 丁丁      |  18 |
    | 10 | 星星      |  18 |
    | 11 | 格格      |  28 |
    | 12 | 张野      |  28 |
    | 13 | 程咬金    |  18 |
    | 14 | 程咬银    |  18 |
    | 15 | 程咬铜    |  18 |
    | 16 | 程咬铁    |  18 |
    +----+-----------+-----+
    9 rows in set (0.11 sec)

     

    找出薪资大于8000的老师

    多个条件

    mysql> select name,post,salary from employee where post='teacher' and salary>8000;
    +------------+---------+------------+
    | name       | post    | salary     |
    +------------+---------+------------+
    | alex       | teacher | 1000000.31 |
    | jingliyang | teacher |    9000.00 |
    | jinxin     | teacher |   30000.00 |
    | 成龙       | teacher |   10000.00 |
    +------------+---------+------------+
    4 rows in set (0.00 sec)

    薪资大于等于20000 小于等于30000

    mysql> select name,salary from employee where  salary >= 20000 and salary <= 30000;
    +-----------+----------+
    | name      | salary   |
    +-----------+----------+
    | jinxin    | 30000.00 |
    | 程咬金    | 20000.00 |
    +-----------+----------+
    2 rows in set (0.00 sec)

    between 20000 and 30000

    原理 >= 20000  <=30000

    mysql> select name,salary from employee where salary between 20000 and 30000;
    +-----------+----------+
    | name      | salary   |
    +-----------+----------+
    | jinxin    | 30000.00 |
    | 程咬金    | 20000.00 |
    +-----------+----------+
    2 rows in set (0.00 sec)

    小于20000 或者大于30000

    mysql> select name,salary from employee where salary < 20000 or salary >30000;
    +------------+------------+
    | name       | salary     |
    +------------+------------+
    | alex       | 1000000.31 |
    | yuanhao    |    3500.00 |
    | liwenzhou  |    2100.00 |
    | jingliyang |    9000.00 |
    | 成龙       |   10000.00 |
    | 歪歪       |    3000.13 |
    | 丫丫       |    2000.35 |
    | 丁丁       |    1000.37 |
    | 星星       |    3000.29 |
    | 格格       |    4000.33 |
    | 张野       |   10000.13 |
    | 程咬银     |   19000.00 |
    | 程咬铜     |   18000.00 |
    | 程咬铁     |   17000.00 |
    +------------+------------+
    14 rows in set (0.00 sec)

    between 取反

    小于2000   大于30000

    mysql> select name,salary from employee where salary not between 20000 and 30000;
    +------------+------------+
    | name       | salary     |
    +------------+------------+
    | alex       | 1000000.31 |
    | yuanhao    |    3500.00 |
    | liwenzhou  |    2100.00 |
    | jingliyang |    9000.00 |
    | 成龙       |   10000.00 |
    | 歪歪       |    3000.13 |
    | 丫丫       |    2000.35 |
    | 丁丁       |    1000.37 |
    | 星星       |    3000.29 |
    | 格格       |    4000.33 |
    | 张野       |   10000.13 |
    | 程咬银     |   19000.00 |
    | 程咬铜     |   18000.00 |
    | 程咬铁     |   17000.00 |
    +------------+------------+
    14 rows in set (0.00 sec)
    #1:单条件查询
        SELECT name FROM employee
            WHERE post='sale';
    
    #2:多条件查询
        SELECT name,salary FROM employee
            WHERE post='teacher' AND salary>10000;
    
    #3:关键字BETWEEN AND
        SELECT name,salary FROM employee 
            WHERE salary BETWEEN 10000 AND 20000;
    
        SELECT name,salary FROM employee 
            WHERE salary NOT BETWEEN 10000 AND 20000;
  • 相关阅读:
    monkeyrunner 进行多设备UI测试
    python Pool并行执行
    python 字符串函数
    python Map()和reduce()函数
    python re模块使用
    3.6 C++继承机制下的构造函数
    3.5 C++间接继承
    3.4 C++名字隐藏
    3.3 C++改变基类成员在派生类中的访问属性
    3.2 C++继承方式
  • 原文地址:https://www.cnblogs.com/mingerlcm/p/9871636.html
Copyright © 2020-2023  润新知