php读取csv乱码问题解决方法

<form action="erxian_cy.php" method="post" enctype="multipart/form-data">
      <table class="table_con" style="100%;">
        
        <tbody>
        	<tr >
        	  <td><input type="file" name="file1" id="file1" />
              <input name="t" type="hidden" value="11"></td>
            </tr>
            <tr>
              <td colspan="3" align="center" style="text-align:center; padding-bottom:10px;"><input type="submit" value=" 提 交 " class="submit" /></td>
            </tr>
        
      </table>
      </form>

if($_POST){
　　　　 $file1 = $_FILES["file1"];
	$csv_file = fopen($file1["tmp_name"], 'r');
	while(!feof($csv_file))$csv_result[] = fgetcsv_reg($csv_file);
	print_r($csv_result);
	foreach($result as $k=>$item){

	}
}

function fgetcsv_reg(&$handle, $length = null, $d = ',', $e = '"') {
	$d = preg_quote($d);
	$e = preg_quote($e);
	$_line = "";
	$eof=false;
	while ($eof != true) {
	$_line .= (empty ($length) ? fgets($handle) : fgets($handle, $length));
	$itemcnt = preg_match_all('/' . $e . '/', $_line, $dummy);
	if ($itemcnt % 2 == 0)
	$eof = true;
	}
	$_csv_line = preg_replace('/(?: |[ ])?$/', $d, trim($_line));
	$_csv_pattern = '/(' . $e . '[^' . $e . ']*(?:' . $e . $e . '[^' . $e . ']*)*' . $e . '|[^' . $d . ']*)' . $d . '/';
	preg_match_all($_csv_pattern, $_csv_line, $_csv_matches);
	$_csv_data = $_csv_matches[1];
	for ($_csv_i = 0; $_csv_i < count($_csv_data); $_csv_i++) {
	$_csv_data[$_csv_i] = preg_replace('/^' . $e . '(.*)' . $e . '$/s', '$1', $_csv_data[$_csv_i]);
	$_csv_data[$_csv_i] = str_replace($e . $e, $e, $_csv_data[$_csv_i]);
	}
	return empty ($_line) ? false : $_csv_data;
}

fgetcsv_reg 替代 fgetcsv 防止php读取csv出现乱码

只有 type="file" 没有其他任何东西,$_POST为空