• 线程模块练习


    1.主线程
    import threading
    t = threading.current_thread()
    print(t) # <_MainThread(MainThread, started 139908235814720)>
    print(t.getName()) # MainThread
    print(t.ident) # 139908235814720
    print(t.isAlive()) # True
    
    2.创建线程
    my_thread = threading.Thread()
    my_thread = threading.Thread(name='my_thread')
    def print_i(i):
        print('打印i:%d'%(i,))
    my_thread = threading.Thread(target=print_i,args=(1,))
    my_thread().start()
    
    
    3 交替获得CPU时间片
    import time
    from datetime import datetime
    import threading
    
    
    def print_time():
        for _ in range(5): # 在每个线程中打印5次
            time.sleep(0.1) # 模拟打印前的相关处理逻辑
            print('当前线程%s,打印结束时间为:%s'%(threading.current_thread().getName(),datetime.today()))
    
    
    threads = [threading.Thread(name='t%d'%(i,),target=print_time) for i in range(3)]
    [t.start() for t in threads]
    
    4.多线程抢夺同一个变量,要加锁
    import threading
    import time
    
    locka = threading.Lock()
    a = 0
    def add1():
        global a    
        try:
            locka.acquire() # 获得锁
            tmp = a + 1
            time.sleep(0.2) # 延时0.2秒,模拟写入所需时间
            a = tmp
        finally:
            locka.release() # 释放锁
        print('%s  adds a to 1: %d'%(threading.current_thread().getName(),a))
        
    threads = [threading.Thread(name='t%d'%(i,),target=add1) for i in range(10)]
    [t.start() for t in threads]
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  • 原文地址:https://www.cnblogs.com/miaoweiye/p/12612209.html
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