• 2018 蓝桥杯省赛 B 组模拟赛(五) 结果填空:藏宝图


    bfs预处理两个点之间的距离,全排列求最短总路程.

    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<algorithm>
    #include<iostream>
    #include<queue>
    #include<map>
    #include<cmath>
    #include<set>
    #include<stack>
    #define ll long long
    #define pb push_back
    #define max(x,y) ((x)>(y)?(x):(y))
    #define min(x,y) ((x)>(y)?(y):(x))
    #define cls(name,x) memset(name,x,sizeof(name))
    #define fs first
    #define sc second
    #define mp make_pair
    #define L(x) (1<<x)
    #define next Next
    #define index Index
    using namespace std;
    const int inf=1e9+10;
    const ll llinf=1e17+10;
    const int maxn=1e1+10;
    const int maxm=1e1+10;
    const int mod=1e9+7;
    int n;
    int dist[maxn][maxn];
    pair<int,int> p[maxn];
    char mapp[maxn][maxn];
    int dir[4][2]={{1,0},{-1,0},{0,1},{0,-1}};
    struct node
    {
        int x,y;
        int cost;
    };
    int build(int stx,int sty,int edx,int edy)
    {
        int vis[maxn][maxn];
        cls(vis,0);
        queue<node> Q;
        node temp;
        temp.x=stx; temp.y=sty;
        temp.cost=0;
        Q.push(temp);
        while(!Q.empty())
        {
            temp=Q.front();
            Q.pop();
            vis[temp.x][temp.y]=1;
            if(temp.x==edx&&temp.y==edy)
                return temp.cost;
            for(int i=0;i<4;i++)
            {
                node next=temp;
                next.x+=dir[i][0];
                next.y+=dir[i][1];
                next.cost++;
                if(next.x<0||next.y<0||next.x>9||next.y>9||vis[next.x][next.y]||mapp[next.x][next.y]=='x')
                    continue;
                Q.push(next);
            }
        }
    }
    void solve()
    {
    
    }
    int main()
    {
        //freopen("in.txt","r",stdin);
        while(~scanf("%d",&n))
        {
            for(int i=0;i<=9;i++)
                scanf("%s",mapp[i]);
            int k=0;
            for(int i=0;i<n;i++)
                for(int j=0;j<n;j++)
                {
                    if(mapp[i][j]>='0'&&mapp[i][j]<='9')
                        p[k++]=mp(i,j);
                }
            p[k]=mp(0,0);
            build(p[0].fs,p[0].sc,p[1].fs,p[1].sc);
            for(int i=0;i<=k;i++)
            {
                for(int j=i+1;j<=k;j++)
                {
                    dist[i][j]=dist[j][i]=build(p[i].fs,p[i].sc,p[j].fs,p[j].sc);
                }
            }
            int a[]={0,1,2,3,4,5,6,7,8,9};
            int ans=inf;
            do
            {
                int s=dist[10][a[0]]+dist[a[9]][10];
                for(int i=0;i<=8;i++)
                {
                    s+=dist[a[i]][a[i+1]];
                }
                ans=min(ans,s);
            }while(next_permutation(a,a+10));
            printf("%d
    ",ans);
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/mgz-/p/8652956.html
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