一般题是 和的最小值 这个是乘积的最大值
Sample Input
3
1 0.5 0.5
0.5 1 0.4
0.5 0.4 1
3
1 2 //起点 终点
2 3
1 3
Sample Output
0.500
0.400
0.500
Dijkstra:
1 # include <iostream> 2 # include <cstdio> 3 # include <cstring> 4 # include <algorithm> 5 # include <cmath> 6 # define LL long long 7 using namespace std ; 8 9 const int MAXN=1010; 10 const int INF=0x3f3f3f3f; 11 int n ; 12 bool vis[MAXN]; 13 double cost[MAXN][MAXN] ; 14 double lowcost[MAXN] ; 15 void Dijkstra(int beg) 16 { 17 for(int i=0;i<n;i++) 18 { 19 lowcost[i]=cost[beg][i];vis[i]=false;; 20 } 21 for(int j=0;j<n;j++) 22 { 23 int k=-1; 24 double Max= -INF; 25 for(int i=0;i<n;i++) 26 if(!vis[i]&&lowcost[i] > Max) 27 { 28 Max=lowcost[i]; 29 k=i; 30 } 31 if(k==-1) 32 break ; 33 vis[k]=true; 34 for(int i=0;i<n;i++) 35 lowcost[i]=max(lowcost[i],lowcost[k]*cost[k][i]) ; 36 37 } 38 39 } 40 41 42 43 int main () 44 { 45 // freopen("in.txt","r",stdin) ; 46 47 while (scanf("%d" , &n ) !=EOF) 48 { 49 int i , j ; 50 for (i = 0 ; i < n ; i++) 51 for (j = 0 ; j < n ; j++) 52 scanf("%lf" , &cost[i][j]) ; 53 int m ; 54 scanf("%d" , &m) ; 55 while(m--) 56 { 57 int s , e; 58 scanf("%d %d" , &s , &e) ; 59 Dijkstra(s-1) ; 60 if (lowcost[e-1] > 1 || lowcost[e-1] <= 0) 61 printf("What a pity! ") ; 62 else 63 printf("%.3lf " , lowcost[e-1]) ; 64 } 65 } 66 67 return 0 ; 68 }