• n 个骰子的点数


    把 n 个骰子仍在地上,求点数和为 s 的概率。

    java:

     1 public List<Map.Entry<Integer, Double>> dicesSum(int n) {
     2     final int face = 6;
     3     final int pointNum = face * n;
     4     long[][] dp = new long[n + 1][pointNum + 1];
     5 
     6     for (int i = 1; i <= face; i++)
     7         dp[1][i] = 1;
     8 
     9     for (int i = 2; i <= n; i++)
    10         for (int j = i; j <= pointNum; j++)     /* 使用 i 个骰子最小点数为 i */
    11             for (int k = 1; k <= face && k <= j; k++)
    12                 dp[i][j] += dp[i - 1][j - k];
    13 
    14     final double totalNum = Math.pow(6, n);
    15     List<Map.Entry<Integer, Double>> ret = new ArrayList<>();
    16     for (int i = n; i <= pointNum; i++)
    17         ret.add(new AbstractMap.SimpleEntry<>(i, dp[n][i] / totalNum));
    18 
    19     return ret;
    20 }
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  • 原文地址:https://www.cnblogs.com/mengchunchen/p/10608502.html
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