My Calendar I (M)
题目
Implement a MyCalendar
class to store your events. A new event can be added if adding the event will not cause a double booking.
Your class will have the method, book(int start, int end)
. Formally, this represents a booking on the half open interval [start, end)
, the range of real numbers x
such that start <= x < end
.
A double booking happens when two events have some non-empty intersection (ie., there is some time that is common to both events.)
For each call to the method MyCalendar.book
, return true
if the event can be added to the calendar successfully without causing a double booking. Otherwise, return false
and do not add the event to the calendar.
Your class will be called like this: MyCalendar cal = new MyCalendar();
MyCalendar.book(start, end)
Example 1:
MyCalendar();
MyCalendar.book(10, 20); // returns true
MyCalendar.book(15, 25); // returns false
MyCalendar.book(20, 30); // returns true
Explanation:
The first event can be booked. The second can't because time 15 is already booked by another event.
The third event can be booked, as the first event takes every time less than 20, but not including 20.
Note:
- The number of calls to
MyCalendar.book
per test case will be at most1000
. - In calls to
MyCalendar.book(start, end)
,start
andend
are integers in the range[0, 10^9]
.
题意
给定若干个区间范围,依次加到日程中,每个区间不能重叠,判断每次加入是否成功。
思路
建一个类似BST的树即可,结点的值为区间范围。
代码实现
Java
class MyCalendar {
private Node root;
private int size;
public MyCalendar() {
root = null;
size = 0;
}
public boolean book(int start, int end) {
int old = size;
root = insert(root, start, end);
return size == old + 1;
}
private Node insert(Node root, int start, int end) {
if (root == null) {
size++;
return new Node(start, end);
}
if (start >= root.end) {
root.right = insert(root.right, start, end);
} else if (end <= root.start) {
root.left = insert(root.left, start, end);
}
return root;
}
class Node {
int start, end;
Node left, right;
Node(int start, int end) {
this.start = start;
this.end = end;
}
}
}