Reach a Number (M)
题目
You are standing at position 0 on an infinite number line. There is a goal at position target.
On each move, you can either go left or right. During the n-th move (starting from 1), you take n steps.
Return the minimum number of steps required to reach the destination.
Example 1:
Input: target = 3
Output: 2
Explanation:
On the first move we step from 0 to 1.
On the second step we step from 1 to 3.
Example 2:
Input: target = 2
Output: 3
Explanation:
On the first move we step from 0 to 1.
On the second move we step from 1 to -1.
On the third move we step from -1 to 2.
Note:
target will be a non-zero integer in the range [-10^9, 10^9].
题意
在一根数轴上从0出发，第n步可以向左或向右走n步，问最少需要几步走到指定值。
思路
target正负不影响，为方便取target绝对值。先求出k，使得sum=1+2+...+k恰好大于target，如果sum-target为偶数，说明在1~k这k步中，只要第(sum-target)/2这一步变为向左走，就能正好到达target；如果sum-target为奇数，说明还需要再走1步或2步，使(sum+k+1-target)为偶数或(sum+k+1+k+2-target)为偶数，这样也能在1~k+1或1~k+2中选一步向左走，使得正好走到target。
代码实现
Java
class Solution {
public int reachNumber(int target) {
target = Math.abs(target);
int step = 0, sum = 0;
while (sum < target) {
sum += ++step;
}
return (sum - target) % 2 == 0 ? step : step % 2 == 0 ? step + 1 : step + 2;
}
}