Golang阻塞的管道
疑惑: 对于处理不完任务的管道，剩下的任务是不是按照顺序处理的?
测试思路
- 生产者每 3 毫秒生产一条
- 消费者每秒消费一条
- 观察数据打印
如果数据是递增的，就是队列
不是递增的，那就是内部实现的是锁的竞争
代码
package main
import (
"log"
"time"
)
var Queue chan int // 任务管道
var Token int // 数据源，数据递增
// 任务每秒消费一条
func work(data int) {
log.Println(data)
time.Sleep(time.Second)
}
// 数据0.3秒生产一条
func producer() {
ticker := time.NewTicker(time.Millisecond * 300)
for {
<-ticker.C
go func() {
Token++
Queue <-Token
}()
}
}
func main() {
Queue = make(chan int, 5)
go producer()
for {
data := <- Queue
work(data)
}
}
测试结果1
2021/07/19 22:40:03 1
2021/07/19 22:40:04 2
2021/07/19 22:40:05 3
2021/07/19 22:40:06 4
2021/07/19 22:40:07 5
2021/07/19 22:40:08 6
2021/07/19 22:40:09 7
2021/07/19 22:40:10 8
2021/07/19 22:40:11 11
2021/07/19 22:40:12 14
2021/07/19 22:40:13 17
2021/07/19 22:40:14 21
2021/07/19 22:40:15 24
2021/07/19 22:40:16 27
2021/07/19 22:40:17 31
2021/07/19 22:40:18 34
2021/07/19 22:40:19 38
2021/07/19 22:40:20 41
测试结果2
2021/07/19 22:41:10 1
2021/07/19 22:41:11 2
2021/07/19 22:41:12 3
2021/07/19 22:41:13 4
2021/07/19 22:41:14 5
2021/07/19 22:41:15 6
2021/07/19 22:41:16 7
2021/07/19 22:41:17 8
2021/07/19 22:41:18 11
2021/07/19 22:41:19 14
2021/07/19 22:41:20 17
2021/07/19 22:41:21 21
2021/07/19 22:41:22 24
2021/07/19 22:41:23 27
结论
不是按序到达的