• Java基础之写文件——将素数写入文件中(PrimesToFile)


    控制台程序,计算素数、创建文件路径、写文件。

     1 import static java.lang.Math.ceil;
     2 import static java.lang.Math.sqrt;
     3 import static java.lang.Math.min;
     4 import static java.nio.file.StandardOpenOption.*;
     5 import java.nio.file.*;
     6 import java.nio.channels.*;
     7 import java.nio.*;
     8 import java.util.*;
     9 import java.io.IOException;
    10 
    11 public class PrimesToFile {
    12   public static void main(String[] args) {
    13     int primesRequired = 100;                                          // Default count
    14     if (args.length > 0) {
    15       try {
    16         primesRequired = Integer.valueOf(args[0]).intValue();
    17       } catch (NumberFormatException e) {
    18         System.out.println("Prime count value invalid. Using default of " + primesRequired);
    19       }
    20     }
    21 
    22       long[] primes = new long[primesRequired];                        // Array to store primes
    23       
    24       getPrimes(primes);
    25       Path file = createFilePath("Beginning Java Struff","primes.bin");
    26       writePrimesFile(primes,file);
    27     }
    28       //Calculate enough primes to fill the array
    29       private static long[] getPrimes(long[] primes) {
    30           primes[0] = 2L;                                                  // Seed the first prime
    31           primes[1] = 3L;                                                  // and the second
    32           // Count of primes found ?up to now, which is also the array index
    33           int count = 2;
    34           // Next integer to be tested
    35           long number = 5L;
    36 
    37           outer:
    38           for (; count < primes.length; number += 2) {
    39 
    40             // The maximum divisor we need to try is square root of number
    41             long limit = (long)ceil(sqrt((double)number));
    42 
    43             // Divide by all the primes we have up to limit
    44             for (int i = 1 ; i < count && primes[i] <= limit ; ++i)
    45               if (number % primes[i] == 0L)                                // Is it an exact divisor?
    46                 continue outer;                                            // yes, try the next number
    47 
    48             primes[count++] = number;                                      // We got one!
    49           }
    50           return primes;
    51         }
    52     //Create the path for the named file in the specified directory
    53     //in the user home directory
    54     private static Path createFilePath(String directory, String fileName) {
    55         Path file = Paths.get(System.getProperty("user.home")).resolve(directory).resolve(fileName);
    56         try {
    57           Files.createDirectories(file.getParent());                       // Make sure we have the directory
    58         } catch (IOException e) {
    59           e.printStackTrace();
    60           System.exit(1);
    61         }
    62         System.out.println("New file is: " + file);
    63         return file;
    64     }
    65     
    66     //Write the array contents to file
    67     private static void writePrimesFile(long[] primes, Path file) {
    68         final int BUFFERSIZE = 100;                                        // Byte buffer size
    69         try (WritableByteChannel channel = Files.newByteChannel(file, EnumSet.of(WRITE, CREATE))) {
    70           ByteBuffer buf = ByteBuffer.allocate(BUFFERSIZE);
    71           LongBuffer longBuf = buf.asLongBuffer();                         // View buffer for type long
    72           int primesWritten = 0;                                           // Count of primes written to file
    73           while (primesWritten < primes.length) {
    74             longBuf.put(primes,                                            // Array to be written
    75                         primesWritten,                                     // Index of 1st element to write
    76                         min(longBuf.capacity(), primes.length - primesWritten));
    77             buf.limit(8*longBuf.position());                               // Update byte buffer position
    78             channel.write(buf);
    79             primesWritten += longBuf.position();
    80             longBuf.clear();
    81             buf.clear();
    82           }
    83           System.out.println("File written is " + ((FileChannel)channel).size() + " bytes.");
    84         } catch (IOException e) {
    85           e.printStackTrace();
    86         }
    87     }
    88 }
  • 相关阅读:
    [python]windows截图
    [python]PyPI使用国内源
    [MySQL]配置多个MySQL服务(Windows)
    [C#]中获取当前程序运行路径的方法
    [C#]统计文本文件txt中的行数(快速读取)
    [C#]获取连接MySql数据库及常用的CRUD操作
    html和css高级
    html和css进阶
    html和css入门
    Git 简介
  • 原文地址:https://www.cnblogs.com/mannixiang/p/3386745.html
Copyright © 2020-2023  润新知