• ZOJ Problem Set–1951 Goldbach's Conjecture


    Time Limit: 2 Seconds      Memory Limit: 65536 KB


    In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture:

    Every even number greater than 4 can be
    written as the sum of two odd prime numbers.
    For example:
    8 = 3 + 5. Both 3 and 5 are odd prime numbers.
    20 = 3 + 17 = 7 + 13.
    42 = 5 + 37 = 11 + 31 = 13 + 29 = 19 + 23.
    Today it is still unproven whether the conjecture is right. (Oh wait, I have the proof of course, but it is too long to write it on the margin of this page.)
    Anyway, your task is now to verify Goldbach's conjecture for all even numbers less than a million.

    Input
    The input will contain one or more test cases.
    Each test case consists of one even integer n with 6 <= n < 1000000.
    Input will be terminated by a value of 0 for n.

    Output
    For each test case, print one line of the form n = a + b, where a and b are odd primes. Numbers and operators should be separated by exactly one blank like in the sample output below. If there is more than one pair of odd primes adding up to n, choose the pair where the difference b - a is maximized. If there is no such pair, print a line saying "Goldbach's conjecture is wrong."

    Sample Input
    8
    20
    42
    0

    Sample Output
    8 = 3 + 5
    20 = 3 + 17
    42 = 5 + 37


    Source: University of Ulm Local Contest 1998

      1:  #include<iostream>
    
      2:  #include<bitset>
    
      3:  #include<cmath>
    
      4:   
    
      5:  using namespace std;
    
      6:   
    
      7:  const int PRIME_NUM = 1000000; 
    
      8:   
    
      9:  bitset<PRIME_NUM> Primes;
    
     10:  void InitialPrimers()
    
     11:  {
    
     12:   Primes.set();
    
     13:   int i,k;
    
     14:   for(i=2;i<PRIME_NUM;i++)
    
     15:   {
    
     16:      k=2*i;
    
     17:      while(k<PRIME_NUM)
    
     18:      {
    
     19:        if(Primes.test(k))
    
     20:         Primes.reset(k);
    
     21:       k+=i;
    
     22:      }
    
     23:   }
    
     24:  }
    
     25:   
    
     26:  int main(void)
    
     27:  {
    
     28:    InitialPrimers();
    
     29:    int n;
    
     30: 
    
     31:    while(cin>>n && n)
    
     32:    {
    
     33:      bool find = false;
    
     34:      for(int i = 3;i <= n/2;i+=2)
    
     35:      {
    
     36:          if(Primes.test(n - i) && Primes.test(i))
    
     37:          {
    
     38:            cout<<n<<" = "<<i<<" + "<<n - i<<endl;
    
     39:            find = true;
    
     40:            break;
    
     41:          }
    
     42:      }
    
     43:      if(!find)
    
     44:        cout<<"Goldbach's conjecture is wrong."<<endl;
    
     45:    }
    
     46:   return 0;
    
     47: }
  • 相关阅读:
    linux基础名词
    计算机基础
    c++ 构造函数
    c++ stdafx.h、targetver.h文件
    centos7初步命令
    mysql 操作表的语句
    后台返回API数据格式
    nginx相关知识
    js复制内容到剪贴板格式化粘贴到excel中
    PHP开启错误提示
  • 原文地址:https://www.cnblogs.com/malloc/p/2494116.html
Copyright © 2020-2023  润新知