• py-day2-4 python 集合


    # 集合是由 { ,} 组成
    test = {1,2,8,9,7,5}
    print(test)
    
    {1, 2, 5, 7, 8, 9}
    # 集合的结果是 去重的,且排序是 无序的
    test = {1,2,3,3,5,8,5,9,7,6}
    print(test)
    
    {1, 2, 3, 5, 6, 7, 8, 9}
    s = set('hello')
    print(s)
    
    {'l', 'o', 'h', 'e'}
    # add()添加
    test = {1,2,3,8,5,9,7,6}
    test.add(16)
    print(test)
    
    {1, 2, 3, 5, 6, 7, 8, 9, 16}
    # .clear()清空
    test = {1,2,3,8,5,9,7,6}
    test.clear()
    print(test)
    
    set()
    # .copy() 复制
    test = {1,2,3,8,5,9,7,6}
    s =test.copy()
    print(s)
    
    {1, 2, 3, 5, 6, 7, 8, 9}
     # .pop() 随机删除
    test = {'abc',10,2,3,8,5,9,7,6}
    test.pop()
    print(test)
    
    {3, 5, 6, 7, 8, 9, 10, 'abc'}
    # .remove() 指定删除(如果删除元素不存在会报错)
    test = {'abc',10,2,3,8,5,9,7,6}
    test.remove(10)
    print(test)
    
    {2, 3, 5, 6, 7, 8, 9, 'abc'}
    ## .discard() 指定删除 (如果元素不存在,不会报错)
    test = {'abc',10,2,3,8,5,9,7,6}
    test.discard(888)
    print(test)
    
    {2, 3, 5, 6, 7, 8, 9, 10, 'abc'}
    # 求交集 intersection()  或者  &
    testname = ['小马','小张','小李','小王']
    lastname = ['小唐','小马','小付']
    t_e = set(testname)
    l_e = set(lastname)
    print(t_e,l_e)
    print(t_e.intersection(l_e))
    print(t_e&l_e)
    
    {'小张', '小马', '小王', '小李'} {'小唐', '小马', '小付'}
    {'小马'}
    {'小马'}
    # 求并集 union()  或者  |
    testname = ['小马','小张','小李','小王']
    lastname = ['小唐','小马','小付']
    t_e = set(testname)
    l_e = set(lastname)
    print(t_e,l_e)
    print(t_e.union(l_e))
    print(t_e|l_e)
    
    {'小马', '小李', '小王', '小张'} {'小马', '小唐', '小付'}
    {'小马', '小王', '小付', '小张', '小李', '小唐'}
    {'小马', '小王', '小付', '小张', '小李', '小唐'}
    #  求差集 difference()  或者 -
    testname = ['小唐','小王','小马','小付']
    lastname = ['小唐','小马','小付']
    t_e = set(testname)
    l_e = set(lastname)
    print(t_e,l_e)
    print(t_e.difference(l_e))
    print(t_e-l_e)
    
    {'小马', '小唐', '小王', '小付'} {'小马', '小唐', '小付'}
    {'小王'}
    {'小王'}

    print(l_e-t_e)
    
    set()
    # 求交补差集 symmetric_difference()  或者 ^
    testname = ['小李','小王','小马','小付']
    lastname = ['小唐','小马','小付']
    t_e = set(testname)
    l_e = set(lastname)
    print(t_e,l_e)
    print(t_e.symmetric_difference(l_e))
    print(t_e^l_e)
    
    {'小马', '小王', '小李', '小付'} {'小马', '小付', '小唐'}
    {'小唐', '小王', '小李'}
    {'小唐', '小王', '小李'}
    # 差集更新 .difference_update()
    
    testname = ['小唐','小王','小马','小付']
    lastname = ['小唐','小马','小付']
    t_e = set(testname)
    l_e = set(lastname)
    print(t_e,l_e)
    t_e
    = t_e-l_e # 原始方法 print(t_e) t_e.difference_update(l_e) # 函数方法 print(t_e) {'小付', '小王', '小唐', '小马'} {'小付', '小唐', '小马'} {'小王'} {'小王'}
    # .isdisjoint() 判断公有,有未False,没有为True
    a = {1,2,3,8}
    b = {2,4,6,9}
    print(a.isdisjoint(b))
    
    False
    
    a = {1,2,3,8}
    b = {0,4,6,9}
    print(a.isdisjoint(b))
    
    True
    # .issubset()  判断是否是子集
    s1 = {1,2}
    s2 = {1,2,3,4}
    print(s1.issubset(s2))    #s1是s2的子集
    print(s2.isdisjoint(s1))  # False
    
    True
    False
    # .issuperset() 判断是否是父集
    s1 = {1,2}
    s2 = {1,2,3,4}
    print(s2.issuperset(s1))  #s2是s1的父集
    
    True
    #  .update() 更新   (可以更新多个值,列表、元祖都行) add只能更新一个值
    s1 = {1,2}
    s2 = {1,2,3,4}
    s1.update(s2)
    print(s1)
    print(s1,s2)
    
    {1, 2, 3, 4}
    {1, 2, 3, 4} {1, 2, 3, 4}
    s1 = {1,2}
    s2 = {1,2,3,4}
    s1.update((6,8))
    print(s1)
    print(s1,s2)
    
    {8, 1, 2, 6}
    {8, 1, 2, 6} {1, 2, 3, 4}
    # frozenset() 改变成不可变集合
    s = frozenset('hello')
    print(s)
    
    frozenset({'l', 'e', 'o', 'h'})
    
    
    # # 集合后的列表
    test =['majun','xiaoma','xiaoma']
    name = list(set(test))
    print(name)
    
    ['majun', 'xiaoma']
    
    
    # 集合变列表  无序
    test = {'majun','xiaoma','zhangfei'}
    name = list(test)
    print(name)
    
    ['zhangfei', 'xiaoma', 'majun']
    
    # 列表变集合  无序
    test =['majun','xiaoma','zhangfei']
    name = set(test)
    print(name)
    
    {'zhangfei', 'xiaoma', 'majun'}
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  • 原文地址:https://www.cnblogs.com/majunBK/p/10416998.html
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