• js Array 交集 并集 差集 去重


    最劲项目需要用到js数组去重和交集的一些运算,我的数组元素个数可能到达1000以上,网上的实现方式都是2次循环,性能不适合我的需求,1000*1000那循环次数太多了,所以我这里采用对象object来做处理,用空间换时间,code 如下:

            ///集合取交集
            Array.intersect = function () {
                var result = new Array();
                var obj = {};
                for (var i = 0; i < arguments.length; i++) {
                    for (var j = 0; j < arguments[i].length; j++) {
                        var str = arguments[i][j];
                        if (!obj[str]) {
                            obj[str] = 1;
                        }
                        else {
                            obj[str]++;
                            if (obj[str] == arguments.length)
                            {
                                result.push(str);
                            }
                        }//end else
                    }//end for j
                }//end for i
                return result;
            }
    
            //集合去掉重复
            Array.prototype.uniquelize = function () {
                var tmp = {},
                    ret = [];
                for (var i = 0, j = this.length; i < j; i++) {
                    if (!tmp[this[i]]) {
                        tmp[this[i]] = 1;
                        ret.push(this[i]);
                    }
                }
    
                return ret;
            }
            //并集
            Array.union = function () {
                var arr = new Array();
                var obj = {};
                for (var i = 0; i < arguments.length; i++) {
                    for (var j = 0; j < arguments[i].length; j++)
                    {
                        var str=arguments[i][j];
                        if (!obj[str])
                        {
                            obj[str] = 1;
                            arr.push(str);
                        }
                    }//end for j
                }//end for i
                return arr;
            }
    
            //2个集合的差集 在arr不存在
            Array.prototype.minus = function (arr) {
                var result = new Array();
                var obj = {};
                for (var i = 0; i < arr.length; i++) {
                    obj[arr[i]] = 1;
                }
                for (var j = 0; j < this.length; j++) {
                    if (!obj[this[j]])
                    {
                        obj[this[j]] = 1;
                        result.push(this[j]);
                    }
                }
                return result;
            };
    
            console.log(Array.intersect(["1", "2", "3"], ["2", "3", "4", "5", "6"]));//[2,3]
            console.log([1, 2, 3, 2, 3, 4, 5, 6].uniquelize());//[1,2,3,4,5,6]
            console.log(Array.union(["1", "2", "3"], ["2", "3", "4", "5", "6"], ["5", "6", "7", "8", "9"]))
            console.log(["2", "3", "4", "5", "6"].minus(["1", "2", "3"]));
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  • 原文地址:https://www.cnblogs.com/majiang/p/5910224.html
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