合并2个已排序的表
先将初始数组的两段完成排序后放在新数组中,再拷贝回去,由于采用递归方法处理,所以会将最下面的2个元素的先排序,1个的直接被返回了
这个过程一直重复直到完成
void MSort(ElementType A[], ElementType TmpArray[], int Left, int Right) { int center; if (Left < Right) { center = (Left + Right)/2; MSort(A, TmpArray, Left, center); MSort(A, TmpArray, center+1, Right); Merge(A, TmpArray, Left, center+1, Right); } } void MergeSort(ELementTYpe A[], int N) { ELementTYpe *TmpArray = malloc(N*sizeof(ELementTYpe)); if (TmpArray != NULL) { MSort(A, TmpArray, 0, N-1); free(TmpArray); } } void Merge(ElementType A[]; ElementType TmpArray[]; int Lpos; int Rpos; int RightEnd) { int i, LeftEnd, NumElements, TmpPos; LeftEnd = Rpos - 1; TmpPos = Lpos; NumElements = RightEnd - Lpos + 1; while (Lpos<=LeftEnd && Rpos<=RightEnd) { if (A[Lpos]<=A[Rpos]) { TmpArray[TmpPos++] = A[LPos++]; } else { TmpArray[TmpPos++] = A[Rpos++] } } while (Lpos <= LeftEnd) { TmpArray[TmpPos++] = A[Lpos++]; } while (Rpos <+ RightEnd) { TmpArray[TmpPos++] = A[Rpos++]; } for (i=0; i<NumElements; i++,RightEnd--) { A[RightEnd] = TmpArray[RightEnd]; } }