（1）列表中的count方法(速度慢)
#嵌套列表类型的统计
l = [[1,2,3,4,5],[1,2,3,4,5],[5,6,7,8,9]]
dictionary= {}
s = set(l)
for i in s:
dict[i] = l.count(i)
（2）字典（速度慢）
l = [[1,2,3,4,5],[1,2,3,4,5],[5,6,7,8,9]]
dict = {}
for i in l:
if i in dict.keys():
dict[i] = int(dict[i]) +1
else:
dict[i] = 1
（3）Counter（速度快）
from collections import Counter
l = [[1,2,3,4,5],[1,2,3,4,5],[5,6,7,8,9]]
cnt = Counter() for i in l:
#要将列表转为元组才可以 i = tuple(i) cnt[i] += 1
#对字典排序（倒序），变为值由大到小的列表
cnt_data=sorted(cnt.items(),key=lambda x:x[1],reverse=True)