• [RTT例程练习] 2.9 事件机制event


    事件也是一种在线程间同步的方式。

    RTT中,事件是一个32bit(4个字节)的变量,其中每一个位可以表示代表一种事件。接收事件的线程既可以在多个事件同时发生后(即多个bit位同时置1)触发,正如本例中线程1中第一条语句所演示的那样。也可以多个事件任意一个发生后(即多个bit位任意一个置位)就可以触发。主程序中创建三个线程,线程1接收事件标志。线程2和线程3则向发送事件标志。可以说,事件更为灵活。

    这里,一共创建了三个线程,一个事件。一开始 thread1 等待事件 bit3 和 bit5 发生,并且是 and 方式。thread2 和 thread3 分别发送了bit3 和 bit5 ,thread1收到之后,等待1s 进入下一次等待事件的发生。第二次事件是 or 的方式,即 bit3 和 bit5 只要有一个方式,事件就算发生,这时 thread3 发出 bit5 事件,thread1 收到后停止调度。

    程序:

    #include <rtthread.h>
    #include <string.h>
    void rt_init_thread_entry(void *parameter)
    {
    
    }
    
    static struct rt_event event;
    
    static rt_uint8_t thread1_stack[1024];
    struct rt_thread thread1;
    static void thread1_entry(void *parameter)
    {
        rt_uint32_t e;
        
        if (rt_event_recv(&event, ((1 << 3) | (1 << 5)),
            RT_EVENT_FLAG_AND | RT_EVENT_FLAG_CLEAR,
            RT_WAITING_FOREVER, &e) == RT_EOK)
        {
            rt_kprintf("thread1: AND recv event 0x%x\n", e);
        }
        
        rt_kprintf("thread1: delay 1s to prepare second event.\n");
        rt_thread_delay(RT_TICK_PER_SECOND);
        
        if (rt_event_recv(&event, ((1 << 3) | (1 << 5)),
            RT_EVENT_FLAG_OR | RT_EVENT_FLAG_CLEAR,
            RT_WAITING_FOREVER, &e) == RT_EOK)
        {
            rt_kprintf("thread1: OR recv event 0x%x\n", e);
        }
        rt_kprintf("thread1 leave.\n");
        
    }
    
    static rt_uint8_t thread2_stack[1024];
    struct rt_thread thread2;
    static void thread2_entry(void *param)
    {
        rt_kprintf("thread2: send event1\n");
        rt_event_send(&event, (1 << 3));
        rt_kprintf("thread2 leave.\n");
    }
    
    static rt_uint8_t thread3_stack[1024];
    struct rt_thread thread3;
    static void thread3_entry(void *param)
    {
        rt_kprintf("thread3: send event2\n");
        rt_event_send(&event, (1 << 5));
    
        rt_thread_delay(20);
    
        rt_kprintf("thread3: send event2\n");
        rt_event_send(&event, (1 << 5));
    
        rt_kprintf("thread3 leave.\n");
    }
    
    int rt_application_init()
    {
        rt_thread_t init_thread;
        rt_err_t result;
        
        result = rt_event_init(&event, "event",
            RT_IPC_FLAG_FIFO);
        if (result != RT_EOK)
        {
            rt_kprintf("init event failed.\n");
            return -1;
        }
        
        init_thread = rt_thread_create("init",
            rt_init_thread_entry, RT_NULL,
            2048, 7, 20);
        if (init_thread != RT_NULL)
            rt_thread_startup(init_thread);
        
        rt_thread_init(&thread1,
            "t1",
            thread1_entry, RT_NULL,
            &thread1_stack[0], sizeof(thread1_stack),
            8, 50);
        rt_thread_startup(&thread1);
        
        rt_thread_init(&thread2,
                       "thread2",
                       thread2_entry,
                       RT_NULL,
                       &thread2_stack[0],
                       sizeof(thread2_stack),9,50);
        rt_thread_startup(&thread2);
    
        rt_thread_init(&thread3,
                       "thread3",
                       thread3_entry,
                       RT_NULL,
                       &thread3_stack[0],
                       sizeof(thread3_stack),10,50);
        rt_thread_startup(&thread3);
        
        return 0;
    }
    结果:

    thread2: send event1
    thread2 leave.
    thread3: send event2
    thread1: AND recv event 0x28
    thread1: delay 1s to prepare second event
    thread3: send event2
    thread3 leave.
    thread1: OR recv event 0x20
    thread1 leave.


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  • 原文地址:https://www.cnblogs.com/lyyyuna/p/4123921.html
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