• Codeforces 19D Points 线段树+set


    题目链接:点击打开链接

    线段树维护y值大于val的最小x值

    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <vector>
    #include <iostream>
    #include <map>
    #include <set>
    #include <math.h>
    using namespace std;
    #define inf 1000000010
    #define ll int
    #define N 200005
    #define L(x) (x<<1)
    #define R(x) (x<<1|1)
    inline ll Mid(ll a,ll b){return (a+b)>>1;}
    ll n;
    struct node{
    	ll x,y;
    	node(ll a=0,ll b=0):x(a),y(b){}
    	bool operator<(const node &a) const{
    		if(a.x==x)
    			return a.y>y;
    		return a.x>x;
    	}
    	ll op;
    }in[N];
    set<node>myset;
    set<node>::iterator p;
    struct Edge{
    	int l, r, id;
    	int maxx, lval;
    	set<ll>st;
    }tree[N<<4];
    set<ll>::iterator pp;
    set<ll>lisan;
    void build(int l,int r,int id){
    	tree[id].l =l ,tree[id].r =r;
    	tree[id].maxx = tree[id].lval = -1;
    	tree[id].st.clear();
    	tree[id].st.insert(-1);
    	if(l==r)return ;
    	int mid = Mid(l,r);
    	build(l,mid,L(id));
    	build(mid+1,r,R(id));
    }
    void updata(ll pos, ll id, ll val, ll o){ // o = 1表示插入
    	if(tree[id].l== tree[id].r) {
    		if(o==1){
    			tree[id].st.insert(val);
    			tree[id].lval = tree[id].maxx = max(tree[id].maxx,val);			
    			return ;
    		}
    		else tree[id].st.erase(val);
    		pp = tree[id].st.end(); pp--;
    		tree[id].lval = tree[id].maxx = *pp;
    		return;
    	}
    	ll mid = Mid(tree[id].l,tree[id].r);
    	if(mid<pos)updata(pos,R(id),val,o);
    	else updata(pos, L(id),val,o);
    	tree[id].lval = tree[L(id)].lval;
    	tree[id].maxx = max(tree[L(id)].maxx, tree[R(id)].maxx);
    }
    ll query(ll l, ll r, ll id, ll val){
    	if(l <=tree[id].l && tree[id].r<=r) {
    		if(tree[id].maxx <= val)return -1;
    		if(tree[id].lval >val)return tree[id].l;
    	}
    	ll mid = Mid(tree[id].l,tree[id].r);
    	if(mid<l)return query(l,r,R(id),val);
    	else if(r<=mid)return query(l,r,L(id),val);
    	ll ans = query(l,mid,L(id),val);
    	if(ans!=-1)return ans;
    	return query(mid+1,r,R(id),val);
    }
    ll pos[N<<1];
    map<ll,ll>mp;
    int main(){
    	ll x,y;
    	while(~scanf("%d",&n)) {
    		myset.clear();
    		mp.clear();
    		lisan.clear();
    		for(ll i = 0; i < n; i++) {
    			char s[10];scanf("%s",s);
    			scanf("%d %d",&in[i].x,&in[i].y);
    			lisan.insert(in[i].x);
    			if(s[0]=='a')in[i].op = 1;
    			else if(s[0]=='r')in[i].op=2;
    			else in[i].op = 3;
    		}
    		ll siz = 1;
    		for(pp=lisan.begin(); pp!=lisan.end(); pp++) {
    			pos[siz] = *pp;
    			mp.insert(pair<ll,ll>(*pp,siz));
    			siz++;
    		}
    		for(ll i = 0; i < n; i++)in[i].x = mp.find(in[i].x)->second;
    		build(1,siz,1);
    		for(ll i = 0; i < n; i++){
    			x = in[i].x, y = in[i].y;
    			if(in[i].op == 1){
    				myset.insert(node(pos[x],y));
    				updata(in[i].x,1,in[i].y,1);
    			}
    			else if(in[i].op == 2){
    				myset.erase(node(pos[x],y));
    				updata(in[i].x,1,in[i].y,0);
    			}
    			else {
    				ll he = query(in[i].x+1,siz,1,in[i].y);
    				if(he==-1){puts("-1");continue;}
    				printf("%d %d
    ",pos[he],myset.lower_bound(node(pos[he],in[i].y+1))->y);
    			}
    		}
    	}
    	return 0;
    }


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  • 原文地址:https://www.cnblogs.com/lxjshuju/p/7099769.html
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