• [leetcode] Valid Sudoku


    Valid Sudoku

    Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

    The Sudoku board could be partially filled, where empty cells are filled with the character '.'.

    A partially filled sudoku which is valid.

    Note:
    A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.
     
     1 class Solution
     2 {
     3 public:
     4   bool isValidSudoku(vector<vector<char> > &board)
     5   {
     6     int i = 0, j = 0;
     7     map<char, int> count;
     8     
     9     //判断行是否合法
    10     for(i = 0; i < 9; i++)
    11     {
    12       count.clear();
    13       for(j = 0; j < 9; j++)
    14       {
    15         count[board[i][j]]++;
    16         if(count[board[i][j]] > 1 && board[i][j] != '.')
    17           return false;
    18       }
    19     }
    20 
    21     //判断列是否合法
    22     for(i = 0; i < 9; i++)
    23     {
    24       count.clear();
    25       for(j = 0; j < 9; j++)
    26       {
    27         count[board[j][i]]++;
    28         if(count[board[j][i]] > 1 && board[j][i] != '.')
    29           return false;
    30       }
    31     }
    32 
    33     // 判断九个小方块是否合法
    34     for(i = 0; i < 9; i = i+3)
    35     {
    36       for(j = 0; j < 9; j = j+3)
    37       {
    38         count.clear();
    39         for(int m = 0; m < 3; m++)
    40         {
    41           for(int n = 0; n < 3; n++)
    42           {
    43             count[board[i + m][j + n]]++;
    44             if(count[board[i + m][j + n]] > 1 && board[i + m][j + n] != '.')
    45               return false;
    46           }
    47         }
    48       }
    49     }
    50 
    51     return true;
    52   }
    53 };
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  • 原文地址:https://www.cnblogs.com/lxd2502/p/4260003.html
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